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anonymous
 5 years ago
t^2dy/dt+2tyy^5=0,t>0 solve the bernoulli equation by using a substitution v=y^1n
anonymous
 5 years ago
t^2dy/dt+2tyy^5=0,t>0 solve the bernoulli equation by using a substitution v=y^1n

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can any one help me plz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, first of all, you need your first fan

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0above is the question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nah, sorry, TOO hard for me, cant figure it out, I am not good with those derivatives and stuff, sorry....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0BTW, did you try google? http://www.math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/ode/first/bernoulli/bernoulli.html http://tutorial.math.lamar.edu/Classes/DE/Bernoulli.aspx http://www.sosmath.com/diffeq/first/bernouilli/bernouilli.html ???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to derive it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the question:\[dy/dt (t^2 +2ty  y^5)\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i need to solve it by bernoulli equation substitution method

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can take y = v + n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0substitute Y in the equation and you'll get :\[t^2 + 2t(v+n)  (v+n)^5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to derive with respect to t?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you'll treat (v+n) in the equation as constants

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and so, I think you'll get : = 2t + 2(v+n) (v +n) = 2t +2v + 2n v n = 2t +v +n I guess :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since you're deriving with respect to t, then you'll ignore the others and treat them as constants. please correct me if I'm wrong

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0y and v are functions of t though. Also, yummy the site andrius gave you it awesome and easy to read

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol yeah, google it :)
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