## anonymous 5 years ago how do i graph y=-1 over x + 1 on a graph??

1. anonymous

you mean you want to sketch y= -1 on a graph right?

2. anonymous

im not sure, thats why im looking for help where ever i can get it. i have an assignment due wednesday and that is one of the questions. the teacher is very little help and hasnt told me what to do. can you help?

3. anonymous

what does the question really say?

4. anonymous

the question says: on graph D draw y=-1 over x+1

5. anonymous

graph D is x + 1 right?

6. anonymous

well i know it isnt equal to negative one.

7. anonymous

hmmm if so, then you have point y as -1 and you can find x : y = x + 1 -1 = x + 1 x = -2 so , your point on that graph must be at (-2,-1) I guess.

8. anonymous

since you want to graph y= -1 on x + 1, then they are equal at some point

9. myininaya

? when you over do you mean it is a fraction like -1/(x+1)

10. anonymous

I think that's what he meant! then I have misread the question again lol, sorry

11. anonymous

yes

12. anonymous

then @matto forget my answer, I have misread the question, dearest apology

13. myininaya

Do you know what 1/x looks like?

14. anonymous

hyperbola

15. anonymous

to graph such question you have to find the limits to find the HAs and VAs

16. myininaya

just move the graph over 1 in the positive direction

17. anonymous

yes, it is bacically a an open c shape that only takes up one quater of a quadratic graph. im not sure how t explain it

18. myininaya

sorry over 1 in the negative direction

19. anonymous

he can't do that without finding the HAs and VAs

20. anonymous

you have to find the limit : $\lim_{x \rightarrow \pm \infty} y$ to find the HAs and $\lim_{x \rightarrow -1\pm}$ to find the VAs

21. anonymous

to see where the function's position will be in the end

22. anonymous

that's it :)

23. anonymous

im sorry, but in all seriousness, i have absolutly no idea what that means.

24. anonymous

lol, alright did you take limits?

25. anonymous

thank you! actually I have been strugling with this problem too... thanks now i am starting to get it... btw, I think you could be a GREAT lecturer

26. anonymous

thanks andy ^_^ I'm flattered

27. anonymous

maths is easily my weakest subject, im doing 4 3A/B subjects for year 12 and i was hoping this migh help.

28. anonymous

don't worry, it will help. I was weak in mathematics , but then I got on my feet and worked hard and look where have I reached :)

29. anonymous

@ matto, did you take limits?

30. anonymous

what is a limit?

31. anonymous

this :$\lim_{a \rightarrow b} f(x)$ = L do you recognize this?

32. anonymous

im sorry, no. as i have said, my teacher has done very little teaching over the last 8 weeks.

33. anonymous

oh, btw, I have a book called "calculus" =D its like 1000 pages, anyone want it? If it feels too big, I also have Calculus Essentials, maybe you want this?

34. anonymous

andy, can you explain the problem for him please? :) brb

35. anonymous

the problem looks simple, but also looks uncomplete... I cant really get what the question means..

36. anonymous

it also asks to include all asymptotes if tha helps. i dont know what an asymptote is.

37. anonymous

In analytic geometry, an asymptote of a curve is a line such that the distance between the curve and the line approaches zero as they tend to infinity.

38. anonymous
39. anonymous

ok, well, its ok if you cant help. i appreciate the help. this was basically a last resort for me, i will seek help else where.

40. anonymous

you know, i think you should go to your friends ask them to help if they dont, go to your teacher if she doesnt, go to library

41. anonymous

if library doesnt, drop it, go do something fun...

42. anonymous

back, alright @matto

43. anonymous

44. anonymous

An asymptote is a line you draw on the graph that limits the graph from extending , contracting etc we have 2 types of asymptotes 1) Horizontal asymptotes are the lines that cut the y-axis horizontaly, you find them by taking the limit of f(x) as x goes to infinity like this: $\lim_{x \rightarrow \pm \infty} f(x)$ and you take the limit from the left and right, if you end up with the limit = : if you end up with an answer that is a number, then that number is you Horizontal asymptote. 2) Vertical asymptotes are the lines that cut the x-axis, and you find them by taking the limit of x, as x goes to a number that makes your denominator 0, in your function which is y = -1/x+1 , x=-1 your number : $\lim_{x \rightarrow 1\pm} f(x)$ $\infty , -\infty$ then x = 1 is your Vertical Asymptote

45. anonymous

I hope he got the meaning and difference between HAs and VAs

46. anonymous

i hope so too

47. anonymous

it's not simple to explain it without showing him the graph by hand

48. anonymous

x = -1 * instead of x=1 sorry ^^"