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anonymous
 5 years ago
how do i graph y=1 over x + 1 on a graph??
anonymous
 5 years ago
how do i graph y=1 over x + 1 on a graph??

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you mean you want to sketch y= 1 on a graph right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im not sure, thats why im looking for help where ever i can get it. i have an assignment due wednesday and that is one of the questions. the teacher is very little help and hasnt told me what to do. can you help?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does the question really say?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the question says: on graph D draw y=1 over x+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0graph D is x + 1 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i know it isnt equal to negative one.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm if so, then you have point y as 1 and you can find x : y = x + 1 1 = x + 1 x = 2 so , your point on that graph must be at (2,1) I guess.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since you want to graph y= 1 on x + 1, then they are equal at some point

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0? when you over do you mean it is a fraction like 1/(x+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think that's what he meant! then I have misread the question again lol, sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then @matto forget my answer, I have misread the question, dearest apology

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know what 1/x looks like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to graph such question you have to find the limits to find the HAs and VAs

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0just move the graph over 1 in the positive direction

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, it is bacically a an open c shape that only takes up one quater of a quadratic graph. im not sure how t explain it

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0sorry over 1 in the negative direction

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he can't do that without finding the HAs and VAs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have to find the limit : \[\lim_{x \rightarrow \pm \infty} y \] to find the HAs and \[\lim_{x \rightarrow 1\pm}\] to find the VAs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to see where the function's position will be in the end

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im sorry, but in all seriousness, i have absolutly no idea what that means.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, alright did you take limits?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you! actually I have been strugling with this problem too... thanks now i am starting to get it... btw, I think you could be a GREAT lecturer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks andy ^_^ I'm flattered

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0maths is easily my weakest subject, im doing 4 3A/B subjects for year 12 and i was hoping this migh help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don't worry, it will help. I was weak in mathematics , but then I got on my feet and worked hard and look where have I reached :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@ matto, did you take limits?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this :\[\lim_{a \rightarrow b} f(x) \] = L do you recognize this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im sorry, no. as i have said, my teacher has done very little teaching over the last 8 weeks.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, btw, I have a book called "calculus" =D its like 1000 pages, anyone want it? If it feels too big, I also have Calculus Essentials, maybe you want this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0andy, can you explain the problem for him please? :) brb

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the problem looks simple, but also looks uncomplete... I cant really get what the question means..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it also asks to include all asymptotes if tha helps. i dont know what an asymptote is.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In analytic geometry, an asymptote of a curve is a line such that the distance between the curve and the line approaches zero as they tend to infinity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://upload.wikimedia.org/wikipedia/commons/d/d3/1overxplusx_abs.svg like this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, well, its ok if you cant help. i appreciate the help. this was basically a last resort for me, i will seek help else where.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know, i think you should go to your friends ask them to help if they dont, go to your teacher if she doesnt, go to library

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if library doesnt, drop it, go do something fun...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i will ask my friends

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0An asymptote is a line you draw on the graph that limits the graph from extending , contracting etc we have 2 types of asymptotes 1) Horizontal asymptotes are the lines that cut the yaxis horizontaly, you find them by taking the limit of f(x) as x goes to infinity like this: \[\lim_{x \rightarrow \pm \infty} f(x)\] and you take the limit from the left and right, if you end up with the limit = : if you end up with an answer that is a number, then that number is you Horizontal asymptote. 2) Vertical asymptotes are the lines that cut the xaxis, and you find them by taking the limit of x, as x goes to a number that makes your denominator 0, in your function which is y = 1/x+1 , x=1 your number : \[\lim_{x \rightarrow 1\pm} f(x)\] \[\infty , \infty\] then x = 1 is your Vertical Asymptote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I hope he got the meaning and difference between HAs and VAs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's not simple to explain it without showing him the graph by hand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = 1 * instead of x=1 sorry ^^"
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