anonymous
  • anonymous
how do i graph y=-1 over x + 1 on a graph??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
you mean you want to sketch y= -1 on a graph right?
anonymous
  • anonymous
im not sure, thats why im looking for help where ever i can get it. i have an assignment due wednesday and that is one of the questions. the teacher is very little help and hasnt told me what to do. can you help?
anonymous
  • anonymous
what does the question really say?

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anonymous
  • anonymous
the question says: on graph D draw y=-1 over x+1
anonymous
  • anonymous
graph D is x + 1 right?
anonymous
  • anonymous
well i know it isnt equal to negative one.
anonymous
  • anonymous
hmmm if so, then you have point y as -1 and you can find x : y = x + 1 -1 = x + 1 x = -2 so , your point on that graph must be at (-2,-1) I guess.
anonymous
  • anonymous
since you want to graph y= -1 on x + 1, then they are equal at some point
myininaya
  • myininaya
? when you over do you mean it is a fraction like -1/(x+1)
anonymous
  • anonymous
I think that's what he meant! then I have misread the question again lol, sorry
anonymous
  • anonymous
yes
anonymous
  • anonymous
then @matto forget my answer, I have misread the question, dearest apology
myininaya
  • myininaya
Do you know what 1/x looks like?
anonymous
  • anonymous
hyperbola
anonymous
  • anonymous
to graph such question you have to find the limits to find the HAs and VAs
myininaya
  • myininaya
just move the graph over 1 in the positive direction
anonymous
  • anonymous
yes, it is bacically a an open c shape that only takes up one quater of a quadratic graph. im not sure how t explain it
myininaya
  • myininaya
sorry over 1 in the negative direction
anonymous
  • anonymous
he can't do that without finding the HAs and VAs
anonymous
  • anonymous
you have to find the limit : \[\lim_{x \rightarrow \pm \infty} y \] to find the HAs and \[\lim_{x \rightarrow -1\pm}\] to find the VAs
anonymous
  • anonymous
to see where the function's position will be in the end
anonymous
  • anonymous
that's it :)
anonymous
  • anonymous
im sorry, but in all seriousness, i have absolutly no idea what that means.
anonymous
  • anonymous
lol, alright did you take limits?
anonymous
  • anonymous
thank you! actually I have been strugling with this problem too... thanks now i am starting to get it... btw, I think you could be a GREAT lecturer
anonymous
  • anonymous
thanks andy ^_^ I'm flattered
anonymous
  • anonymous
maths is easily my weakest subject, im doing 4 3A/B subjects for year 12 and i was hoping this migh help.
anonymous
  • anonymous
don't worry, it will help. I was weak in mathematics , but then I got on my feet and worked hard and look where have I reached :)
anonymous
  • anonymous
@ matto, did you take limits?
anonymous
  • anonymous
what is a limit?
anonymous
  • anonymous
this :\[\lim_{a \rightarrow b} f(x) \] = L do you recognize this?
anonymous
  • anonymous
im sorry, no. as i have said, my teacher has done very little teaching over the last 8 weeks.
anonymous
  • anonymous
oh, btw, I have a book called "calculus" =D its like 1000 pages, anyone want it? If it feels too big, I also have Calculus Essentials, maybe you want this?
anonymous
  • anonymous
andy, can you explain the problem for him please? :) brb
anonymous
  • anonymous
the problem looks simple, but also looks uncomplete... I cant really get what the question means..
anonymous
  • anonymous
it also asks to include all asymptotes if tha helps. i dont know what an asymptote is.
anonymous
  • anonymous
In analytic geometry, an asymptote of a curve is a line such that the distance between the curve and the line approaches zero as they tend to infinity.
anonymous
  • anonymous
http://upload.wikimedia.org/wikipedia/commons/d/d3/1-over-x-plus-x_abs.svg like this
anonymous
  • anonymous
ok, well, its ok if you cant help. i appreciate the help. this was basically a last resort for me, i will seek help else where.
anonymous
  • anonymous
you know, i think you should go to your friends ask them to help if they dont, go to your teacher if she doesnt, go to library
anonymous
  • anonymous
if library doesnt, drop it, go do something fun...
anonymous
  • anonymous
back, alright @matto
anonymous
  • anonymous
i will ask my friends
anonymous
  • anonymous
An asymptote is a line you draw on the graph that limits the graph from extending , contracting etc we have 2 types of asymptotes 1) Horizontal asymptotes are the lines that cut the y-axis horizontaly, you find them by taking the limit of f(x) as x goes to infinity like this: \[\lim_{x \rightarrow \pm \infty} f(x)\] and you take the limit from the left and right, if you end up with the limit = : if you end up with an answer that is a number, then that number is you Horizontal asymptote. 2) Vertical asymptotes are the lines that cut the x-axis, and you find them by taking the limit of x, as x goes to a number that makes your denominator 0, in your function which is y = -1/x+1 , x=-1 your number : \[\lim_{x \rightarrow 1\pm} f(x)\] \[\infty , -\infty\] then x = 1 is your Vertical Asymptote
anonymous
  • anonymous
I hope he got the meaning and difference between HAs and VAs
anonymous
  • anonymous
i hope so too
anonymous
  • anonymous
it's not simple to explain it without showing him the graph by hand
anonymous
  • anonymous
x = -1 * instead of x=1 sorry ^^"

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