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anonymous
 5 years ago
If dy/dx = 7x^2/y^3 and y(3)=2, find an equation for y in terms of x
anonymous
 5 years ago
If dy/dx = 7x^2/y^3 and y(3)=2, find an equation for y in terms of x

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0separate the variables might help: dy/dx = 7x^2/y^3 (S) y^3 dy = (S) 7x^2 dx (1/4) y^4 = (7/3)x^3 + C y^4 = (28/3)x^3 + C y = + 4root[(28/3)x^3 + C] maybe we can use logs to simplify?? )

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0e^(y^4) = e^[(28/3)x^3 + C] e^4y = e^[(28/3)x^3] * e^C ; e^C is a constant.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ln both sides... 4y = C * (28/3)x^3 y = C * 28x^3/12 y = C * (7x^3)/3 is the best I get.... if its right :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you got the answer? if so, was I right?
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