16 liters of an ideal gas at a temperature of 500 kelvins had a pressure of 100 newtons per square meter. If the volume was increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure?

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16 liters of an ideal gas at a temperature of 500 kelvins had a pressure of 100 newtons per square meter. If the volume was increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure?

Mathematics
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Use this:\[P_1V_1/T_1=P_2V_2/T_2.\] The 1's refer to initial conditions, and 2's refer to secondary conditions. Plug in whatever you already have, and you should only be left with one more unsolved variable - manipulate the fractions and out comes your value.
thank you so much!!!! :)
No problem. :)

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