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anonymous

  • 5 years ago

i hate math

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  1. nowhereman
    • 5 years ago
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    Too bad for you.

  2. anonymous
    • 5 years ago
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    how do i convert celsius into farenheit or vice versa??? i realllllllly hate math but i need an answer! puhhleaseee help! :/

  3. nowhereman
    • 5 years ago
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    You have to apply an linear transformation. Just look up, which exactly it is on wikipedia e.g.

  4. anonymous
    • 5 years ago
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    okie thanks! :)

  5. anonymous
    • 5 years ago
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    oh my god i don't get it :/ ...

  6. nowhereman
    • 5 years ago
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    You've been to http://en.wikipedia.org/wiki/Fahrenheit ? There it says: [°C] = ([°F] − 32) × 5⁄9 [°F] = [°C] × 9⁄5 + 32 What is it, you don't understand?

  7. amistre64
    • 5 years ago
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    0 = 32 ; 100 = 212 these are our coordinates for a line that has a Celsius axis and a Farenheit axis: (0,32) (100,212) whats the slope of the line? slope = (y1-y2)/(x1-x2) slope = (212-32)/(100-0) = 180/100 reduce 180/100 = 18/10 = 9/5 So we have the slope of our line equal to: 9/5 We plug this and one of our coordinates into the equation for a line: y = slope(x) + b or F = (9/5)C + 32 Since zero is an easy number to play with, lets choose (x=0,y=32) 32 = (9/5)(0) + b 32 = 0 + b b = 32; now we have the formula for changeing Celsius into Farenheit: F = (9/5)C + 32 We can manipultate this equation around to find its inverse, that is, the conversion of f:F->C. (F - 32)(5) --------- = C (9)

  8. amistre64
    • 5 years ago
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    got ahead of myself in there; but I think its still readable lol

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