anonymous
  • anonymous
(secx + tanx)^2 = (1+sinx) / (1-sinx)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
wow, what a question, sstarica, you think you can handle it?
anonymous
  • anonymous
=D
anonymous
  • anonymous
thinking :P

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More answers

anonymous
  • anonymous
i think you should use google first =D
anonymous
  • anonymous
sstarica, if you become my fan, I will become yours, a win win
anonymous
  • anonymous
\[= 1+sinx / 1-sinx\]\[= \sec^x + 2secxtanx + \tan^2x\]\[= 1 + \tan^2x + 2(sinx/\cos^2x) + 2(\sin^2x/\cos^2x)\]\[= 1 + ((2\sin^2x + 2sinx)/\cos^2x)\]\[= 1 + (2sinx(1+sinx)/1-\sin^2x)\]\[=1 + (2sinx(1+sinx)/(1-sinx)(1+sinx))\]\[=1 + (2sinx/1-sinx)\]\[= 1(1-sinx) + 2sinx/1-sinx\]\[= 1-sinx + 2sinx/1-sinx\] ^_^
anonymous
  • anonymous
:O
anonymous
  • anonymous
= 1 + sinx / 1-sinx :)
anonymous
  • anonymous
no need for google :)
anonymous
  • anonymous
wow, you are smart
anonymous
  • anonymous
2nd line should be sec^2 x and not sec^x ^^" typo sorry
anonymous
  • anonymous
but I LOVE google =D
anonymous
  • anonymous
we all are ^_^
anonymous
  • anonymous
wait a min....ANGOO! :D
anonymous
  • anonymous
that's you!
anonymous
  • anonymous
Dr. GOO LOL!
anonymous
  • anonymous
=D
anonymous
  • anonymous
another account? lol, I'm slow sorry ^^" just figure u out =P
anonymous
  • anonymous
figured*
anonymous
  • anonymous
why another account? bored? :D
anonymous
  • anonymous
yes =D
anonymous
  • anonymous
got a better name LOL
anonymous
  • anonymous
I'll call you GOOBOO :D!!!!
anonymous
  • anonymous
fanned you
anonymous
  • anonymous
fine fine lol
anonymous
  • anonymous
happy? =P
anonymous
  • anonymous
yes, VERY =D
anonymous
  • anonymous
seriously, lol
anonymous
  • anonymous
ok, I got to go for now, book plane tickets for my dad
anonymous
  • anonymous
see you later smart lady
anonymous
  • anonymous
alright , see you then ^_^
anonymous
  • anonymous
alright Dr.G

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