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anonymous

  • 5 years ago

(secx + tanx)^2 = (1+sinx) / (1-sinx)

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  1. anonymous
    • 5 years ago
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    wow, what a question, sstarica, you think you can handle it?

  2. anonymous
    • 5 years ago
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    =D

  3. anonymous
    • 5 years ago
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    thinking :P

  4. anonymous
    • 5 years ago
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    i think you should use google first =D

  5. anonymous
    • 5 years ago
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    sstarica, if you become my fan, I will become yours, a win win

  6. anonymous
    • 5 years ago
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    \[= 1+sinx / 1-sinx\]\[= \sec^x + 2secxtanx + \tan^2x\]\[= 1 + \tan^2x + 2(sinx/\cos^2x) + 2(\sin^2x/\cos^2x)\]\[= 1 + ((2\sin^2x + 2sinx)/\cos^2x)\]\[= 1 + (2sinx(1+sinx)/1-\sin^2x)\]\[=1 + (2sinx(1+sinx)/(1-sinx)(1+sinx))\]\[=1 + (2sinx/1-sinx)\]\[= 1(1-sinx) + 2sinx/1-sinx\]\[= 1-sinx + 2sinx/1-sinx\] ^_^

  7. anonymous
    • 5 years ago
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    :O

  8. anonymous
    • 5 years ago
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    = 1 + sinx / 1-sinx :)

  9. anonymous
    • 5 years ago
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    no need for google :)

  10. anonymous
    • 5 years ago
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    wow, you are smart

  11. anonymous
    • 5 years ago
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    2nd line should be sec^2 x and not sec^x ^^" typo sorry

  12. anonymous
    • 5 years ago
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    but I LOVE google =D

  13. anonymous
    • 5 years ago
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    we all are ^_^

  14. anonymous
    • 5 years ago
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    wait a min....ANGOO! :D

  15. anonymous
    • 5 years ago
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    that's you!

  16. anonymous
    • 5 years ago
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    Dr. GOO LOL!

  17. anonymous
    • 5 years ago
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    =D

  18. anonymous
    • 5 years ago
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    another account? lol, I'm slow sorry ^^" just figure u out =P

  19. anonymous
    • 5 years ago
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    figured*

  20. anonymous
    • 5 years ago
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    why another account? bored? :D

  21. anonymous
    • 5 years ago
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    yes =D

  22. anonymous
    • 5 years ago
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    got a better name LOL

  23. anonymous
    • 5 years ago
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    I'll call you GOOBOO :D!!!!

  24. anonymous
    • 5 years ago
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    fanned you

  25. anonymous
    • 5 years ago
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    fine fine lol

  26. anonymous
    • 5 years ago
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    happy? =P

  27. anonymous
    • 5 years ago
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    yes, VERY =D

  28. anonymous
    • 5 years ago
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    seriously, lol

  29. anonymous
    • 5 years ago
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    ok, I got to go for now, book plane tickets for my dad

  30. anonymous
    • 5 years ago
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    see you later smart lady

  31. anonymous
    • 5 years ago
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    alright , see you then ^_^

  32. anonymous
    • 5 years ago
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    alright Dr.G

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