A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
(secx + tanx)^2 = (1+sinx) / (1sinx)
anonymous
 5 years ago
(secx + tanx)^2 = (1+sinx) / (1sinx)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow, what a question, sstarica, you think you can handle it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think you should use google first =D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sstarica, if you become my fan, I will become yours, a win win

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[= 1+sinx / 1sinx\]\[= \sec^x + 2secxtanx + \tan^2x\]\[= 1 + \tan^2x + 2(sinx/\cos^2x) + 2(\sin^2x/\cos^2x)\]\[= 1 + ((2\sin^2x + 2sinx)/\cos^2x)\]\[= 1 + (2sinx(1+sinx)/1\sin^2x)\]\[=1 + (2sinx(1+sinx)/(1sinx)(1+sinx))\]\[=1 + (2sinx/1sinx)\]\[= 1(1sinx) + 2sinx/1sinx\]\[= 1sinx + 2sinx/1sinx\] ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= 1 + sinx / 1sinx :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no need for google :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02nd line should be sec^2 x and not sec^x ^^" typo sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait a min....ANGOO! :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0another account? lol, I'm slow sorry ^^" just figure u out =P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why another account? bored? :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0got a better name LOL

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'll call you GOOBOO :D!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, I got to go for now, book plane tickets for my dad

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see you later smart lady

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright , see you then ^_^
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.