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anonymous
 5 years ago
How do you solve a problem that looks like this: 11x^4 + 8x^3  2x^2 + 39 ?
anonymous
 5 years ago
How do you solve a problem that looks like this: 11x^4 + 8x^3  2x^2 + 39 ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok let me start from the beggining

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[11x ^{4}+8x ^{3}2x ^{2}39\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, damn, i gota go eat, my mom is calling.... sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok...just answer it later I guess

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This problem has no solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's not that problem I'm trying to solve, just asking how to solve a problem like it. like how I isolate the variables

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is no specific rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you want to simplify?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is one rule of finding the discriminant. But I am not sure if they are within the scope of your syllabus

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sstarica, what I'm trying to do is solve for x.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.011x^4 + 8x^3  2x^2 + 39; does it equal 0? otherwise it can be any number.. Lets assume that to solve for the "roots" of this equation we are making it equal to zero.. factor out an x^2 from the first 3 terms: (x^2)(11x^2 + 8x  2) + 39 = 0 factor the quadratic: 11x^2 + 8x  2 sqrt(64  (4)(2)(11)) = sqrt(64+88) = (8/22) + (sqrt(152)/22) x= (4/11) + sqrt(152)/22 or (4/11)  sqrt(152)/22 possibly :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or at least thats as far as I got... gotta take into account the +39 and the x^2 stuff

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0could try grouping and see if it works it out....
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