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anonymous
 5 years ago
how do you find the derivative of (y+4)/(x2)=5y at (3,1)???
anonymous
 5 years ago
how do you find the derivative of (y+4)/(x2)=5y at (3,1)???

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0either solve for "y" all by its little lonesome; or use implicit deriv..different.....that one word...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets try implicit... 5y = (y+4)/(x2) ; take the d/dx of both sides.. (d/dx)(5y) = (d/dx)[(y+4)/(x2)]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05y' = apply quotient rule to this side 5y' = [(x2)(1y')  (y+4)(x')] / [(x2)^2] ; dy/dx = y' ; x' = 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0get y' by itself if you dare :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no easier way? how can you get y by it self

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.... I get: y+4 y' =  x7

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0plug in (3,1) y' = 5/6 ?? where did I lose ya? :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y' = 5/4 ; forgot how to add lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get to y+4/x7

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0by using paper and pencil really... but lets see if I can type it out...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x2)(1y')  (y+4)(x') 5y' =  ; move (x2)^2 up and bring y' down.. (x2)^2 (x2)(y')  (y+4) 5(x2)^2 =  ; split the fraction.... y' (x2)(y') (y+4) 5(x2)^2 =    ; cancel top to bottom your y' y' y' (y+4) 5(x2)^2 = (x2)   ; now subtract (x2) from both sides y'  (y+4) [5(x2)^2](x2) =  ; I forgot something on the paper.... y'

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0regardless tho, lets work this out: 4y y' =  [5(x2)^2]  (x2) try that one :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x=3,y=1) y' = (41) / [5(32)^2  (32)] y' = 5 / 4 , is that right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0HAH!!! I got the same answer as I did with the last one lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yessss thank you so much
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