## anonymous 5 years ago How do I change the order of integration for the following equation...(i'll use the equation editor below)

1. anonymous

$I=\int\limits_{0}^{\pi/2}\int\limits_{x}^{\pi/2} [(\sin y) / (y)] dy dx$

2. anonymous

my solution is the following: if we draw the area of the integral, we can see it's bounded by the lines: $x=y, x=0, y=\pi/2$ so x changes from $x=0 \to x=y$, and we can fix y as $y=0 \to y=\pi/2$ the integral I will be as: $I=\int\limits_{0}^{\pi/2}\int\limits_{0}^{y}(siny/y)dxdy$ which will result in a value $I=1$