A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 3 years ago
Need help: use Green's Theorem to find the area under one arch of the cycloid: x= a*(zsin(z)), y = a*(1cos(z))...z is theta
 3 years ago
Need help: use Green's Theorem to find the area under one arch of the cycloid: x= a*(zsin(z)), y = a*(1cos(z))...z is theta

This Question is Closed

ducthinh
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{2\pi}^{0}ydxxdy+\int\limits_{0}^{2\pi}0dx =\int\limits_{2\pi}^{0}\lefta*a( 1\cos(\theta) (1+\cos(\theta)d \theta\a*a(\Theta si(\theta)(\sin(\theta)dtheta)\right)\]

eletronic_rajesh
 3 years ago
Best ResponseYou've already chosen the best response.0\[xdyydx=a*2(zsin z2+2\cos z)dt (now integrate \it with \in \limits 0 \to 2\pi ) then answer will be 3\pi z2\]

ducthinh
 3 years ago
Best ResponseYou've already chosen the best response.0let C1 x=a(zsinz) y=a(1cosz) C2 x=2piz y=0 so we have closed curve C =C1+C2 then area \[A=\int\limits_{0}^{2\pi}(1cosz)(1cosz)dz\int\limits_{0}^{2\pi}0d(z)=3\pi\]

eletronic_rajesh
 3 years ago
Best ResponseYou've already chosen the best response.0but in the above result the radius of the circle through which the cycloid is made is not present. in the integration the 'a' present in the equation should come. and the final answer should be 3pi a^2
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.