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## anonymous 5 years ago A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 93m long and 72m wide. Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

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1. anonymous

2. anonymous

The rectangle is: $93 \cdot 72 m^2$ Both semicirckes equals on semicircle with the area: $A_{circle}= r^2 \cdot \pi = (36 m)^2 \cdot \pi$ All together is: $6696 + 4069,66= 10765,44$

3. anonymous

*equals a circle Don't know how to correct a posting.

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