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anonymous

  • 5 years ago

Determine the critical numbers of the given function and classify each critical point as a relative maximum, relative min or neither. f(t)= t/(t^2+3) I can get to t/(t^2+3) I need to solve for 0 to find the intervals of increase and decrease. I have forgotten how to solve for 0 with this problem.

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  1. anonymous
    • 5 years ago
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    You got nowhere.

  2. anonymous
    • 5 years ago
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    I know i need the 1st derivitive. Which I got t(2t) - (t^2+3)(1) / (t^2+3)^2 Is that much correct?

  3. amistre64
    • 5 years ago
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    f'(x) = [ BT' - B'T ] / B^2

  4. amistre64
    • 5 years ago
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    (t^2 +3)(1) - (t)(2t) ---------------- (t^2 +3)^2

  5. amistre64
    • 5 years ago
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    any second opinions? :)

  6. nowhereman
    • 5 years ago
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    I agree, but _please_ use the equation-editor: \[f'(t) = \frac{t^2 + 3 - 2t\cdot t}{(t^2+3)^2}\]

  7. amistre64
    • 5 years ago
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    t^2 +3 -2t^2 = 0 -t^2 +3 = 0 -t^2 = -3 t^2 = 3 t=+-sqrt(3)

  8. anonymous
    • 5 years ago
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    I have that. I just have the top reversed.

  9. nowhereman
    • 5 years ago
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    and you were missing parentheses

  10. amistre64
    • 5 years ago
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    I cant get that equation editor to work right .....

  11. nowhereman
    • 5 years ago
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    you can simply enclose the latex-code in \ [ and \ ].

  12. amistre64
    • 5 years ago
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    latex is for painting houses ;)

  13. anonymous
    • 5 years ago
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    amistre64 is right: \[f'(x)= \frac{3-t^2}{(t^2+3)^2}\]

  14. amistre64
    • 5 years ago
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    something likethis? testing \[45\Omega -\sin(45) -\infty\]

  15. amistre64
    • 5 years ago
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    I do better after a nap :)

  16. nowhereman
    • 5 years ago
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    sleep well :-)

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