anonymous
  • anonymous
Determine the critical numbers of the given function and classify each critical point as a relative maximum, relative min or neither. f(t)= t/(t^2+3) I can get to t/(t^2+3) I need to solve for 0 to find the intervals of increase and decrease. I have forgotten how to solve for 0 with this problem.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
You got nowhere.
anonymous
  • anonymous
I know i need the 1st derivitive. Which I got t(2t) - (t^2+3)(1) / (t^2+3)^2 Is that much correct?
amistre64
  • amistre64
f'(x) = [ BT' - B'T ] / B^2

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amistre64
  • amistre64
(t^2 +3)(1) - (t)(2t) ---------------- (t^2 +3)^2
amistre64
  • amistre64
any second opinions? :)
nowhereman
  • nowhereman
I agree, but _please_ use the equation-editor: \[f'(t) = \frac{t^2 + 3 - 2t\cdot t}{(t^2+3)^2}\]
amistre64
  • amistre64
t^2 +3 -2t^2 = 0 -t^2 +3 = 0 -t^2 = -3 t^2 = 3 t=+-sqrt(3)
anonymous
  • anonymous
I have that. I just have the top reversed.
nowhereman
  • nowhereman
and you were missing parentheses
amistre64
  • amistre64
I cant get that equation editor to work right .....
nowhereman
  • nowhereman
you can simply enclose the latex-code in \ [ and \ ].
amistre64
  • amistre64
latex is for painting houses ;)
anonymous
  • anonymous
amistre64 is right: \[f'(x)= \frac{3-t^2}{(t^2+3)^2}\]
amistre64
  • amistre64
something likethis? testing \[45\Omega -\sin(45) -\infty\]
amistre64
  • amistre64
I do better after a nap :)
nowhereman
  • nowhereman
sleep well :-)

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