## anonymous 5 years ago Determine the critical numbers of the given function and classify each critical point as a relative maximum, relative min or neither. f(t)= t/(t^2+3) I can get to t/(t^2+3) I need to solve for 0 to find the intervals of increase and decrease. I have forgotten how to solve for 0 with this problem.

1. anonymous

You got nowhere.

2. anonymous

I know i need the 1st derivitive. Which I got t(2t) - (t^2+3)(1) / (t^2+3)^2 Is that much correct?

3. amistre64

f'(x) = [ BT' - B'T ] / B^2

4. amistre64

(t^2 +3)(1) - (t)(2t) ---------------- (t^2 +3)^2

5. amistre64

any second opinions? :)

6. nowhereman

I agree, but _please_ use the equation-editor: $f'(t) = \frac{t^2 + 3 - 2t\cdot t}{(t^2+3)^2}$

7. amistre64

t^2 +3 -2t^2 = 0 -t^2 +3 = 0 -t^2 = -3 t^2 = 3 t=+-sqrt(3)

8. anonymous

I have that. I just have the top reversed.

9. nowhereman

and you were missing parentheses

10. amistre64

I cant get that equation editor to work right .....

11. nowhereman

you can simply enclose the latex-code in \ [ and \ ].

12. amistre64

latex is for painting houses ;)

13. anonymous

amistre64 is right: $f'(x)= \frac{3-t^2}{(t^2+3)^2}$

14. amistre64

something likethis? testing $45\Omega -\sin(45) -\infty$

15. amistre64

I do better after a nap :)

16. nowhereman

sleep well :-)