anonymous
  • anonymous
I need help solving this equation. 4-8x/x+1 = 8/x+1 can anyone help me?
Mathematics
chestercat
  • chestercat
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amistre64
  • amistre64
is it: (4-8x)/(x+1) = 8/(x+1) ?
amistre64
  • amistre64
or.. (4-8x)/(x+1) = (8/x)+1?
amistre64
  • amistre64
first ones easy: denominators dont count.. much. 4-8x = 8 -8x = 8-4 -8x = 4 x = (-1/2)

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nowhereman
  • nowhereman
\[4 - \frac{8x}{x} + 1 = \frac{8}{x} + 1 \] \[ ⇔ x \neq 0 ∧ -3 = \frac{8}{x} + 1 \] \[ ⇔x \neq 0 ∧ x = \frac{8}{-4} ⇔ x = -2\]
anonymous
  • anonymous
The problem is 4- 8x over x+1 = 8 over x+1. I have to solve it.
amistre64
  • amistre64
i solved it fer ya; x = -(1/2) or 1.5 if you want a decimal
amistre64
  • amistre64
that 1 was supposed to be a (-) lol.... a aint a typist
anonymous
  • anonymous
thank you so much I'm not much of a mathamatian. sorry if spelled wrong.LOL
amistre64
  • amistre64
i believe they are called "mathmatickers" but I could be mistaken :)

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