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anonymous

  • 5 years ago

I need help solving this equation. 4-8x/x+1 = 8/x+1 can anyone help me?

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  1. amistre64
    • 5 years ago
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    is it: (4-8x)/(x+1) = 8/(x+1) ?

  2. amistre64
    • 5 years ago
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    or.. (4-8x)/(x+1) = (8/x)+1?

  3. amistre64
    • 5 years ago
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    first ones easy: denominators dont count.. much. 4-8x = 8 -8x = 8-4 -8x = 4 x = (-1/2)

  4. nowhereman
    • 5 years ago
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    \[4 - \frac{8x}{x} + 1 = \frac{8}{x} + 1 \] \[ ⇔ x \neq 0 ∧ -3 = \frac{8}{x} + 1 \] \[ ⇔x \neq 0 ∧ x = \frac{8}{-4} ⇔ x = -2\]

  5. anonymous
    • 5 years ago
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    The problem is 4- 8x over x+1 = 8 over x+1. I have to solve it.

  6. amistre64
    • 5 years ago
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    i solved it fer ya; x = -(1/2) or 1.5 if you want a decimal

  7. amistre64
    • 5 years ago
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    that 1 was supposed to be a (-) lol.... a aint a typist

  8. anonymous
    • 5 years ago
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    thank you so much I'm not much of a mathamatian. sorry if spelled wrong.LOL

  9. amistre64
    • 5 years ago
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    i believe they are called "mathmatickers" but I could be mistaken :)

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