anonymous
  • anonymous
Terrible at math, need help with college algebra.
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
...Which part of college algebra?
anonymous
  • anonymous
The Substitution Method Solutions to Systems of Linear Equations Applications of the Substitution Method
anonymous
  • anonymous
Okay, say you have two linear equations that need solving.\[a*x + b*y = c\] and \[d*x+e*y=f.\] Now, you solve one equation for x:\[x = (c-b*y)/d.\] Plug that value for x into your second equation, and solve for a value of y.

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anonymous
  • anonymous
After you have that value of y, you plug it back into either equation, and you'll get the value of x. :)
amistre64
  • amistre64
its really simpler than it looks :)
anonymous
  • anonymous
(Assuming a-f are regular constants.)
anonymous
  • anonymous
So for x-2y=1 3x+12y+15 i am suppossed to find whether the lines are parallel or coinciding...
anonymous
  • anonymous
You mean, 3x+12y = 15?
amistre64
  • amistre64
It depends on what is being asked for in the problem.
amistre64
  • amistre64
oh...that is the problem..thought it was a question lol
anonymous
  • anonymous
yes and i have to write these in slope intercept form
anonymous
  • anonymous
If they coincide, or are the exact same line, then one equation will be the same as the other equation -- just multiplying every term by the same factor.
amistre64
  • amistre64
do you know how to solve each equation for "y"?
amistre64
  • amistre64
x - 2y = 1; how would you solve for "y"?
anonymous
  • anonymous
I amnot sure....
amistre64
  • amistre64
we have to go back to the basics of equations with this; we want to get that "y" all by itself on one side of the equation and everything else to the other side; does that sound familiar?
amistre64
  • amistre64
the basic rule of thumb is: whatever you do to one side, HAS to be done to the other inorder for it to stay equal.

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