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anonymous
 5 years ago
how do I turn bc^2ac^2b^2c+ab^2+a^2ca^2b into (ba)(ca)(cb)
anonymous
 5 years ago
how do I turn bc^2ac^2b^2c+ab^2+a^2ca^2b into (ba)(ca)(cb)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[bc ^{2}b ^{2}cac ^{2}+ab ^{2}+a ^{2}ca ^{2}b\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if it helps, it's the vandermonde determinant [1 a a^2],[1 b b^2], [1 c c^2], and I have to show that it equals (ba)(ca)(cb) for all scalars a,b,c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to add a 0 to make it factor nicely. In particular bca + acb. \[bc^2  b^2c  bca + b^2a = b(c^2  bc ca + ba)\] \[ac^2 + acb + a^2c  a^2b = a(c^2  cb  ca + ba)\] \[c^2  cb  ca + ba = (ca)(cb)\] So taking all the terms together you get (ba)(ca)(cb)
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