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anonymous

  • 5 years ago

how do you find the 5th derivative of tan(x) using tan^2(x)+1 as the first derivative instead of sec^2(x) ?

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  1. anonymous
    • 5 years ago
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    i already have the second and 4rd derivatives but i'm getting really confused on the 4th

  2. amistre64
    • 5 years ago
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    ....concentration :) .....

  3. myininaya
    • 5 years ago
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    I'm to the fourth derivative now and it's all way to the end of the page. lol

  4. anonymous
    • 5 years ago
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    same here

  5. anonymous
    • 5 years ago
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    so much algebra, what's your fourth derivative?

  6. myininaya
    • 5 years ago
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  7. myininaya
    • 5 years ago
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    i don't wanna simplify

  8. myininaya
    • 5 years ago
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    This problem is gross

  9. anonymous
    • 5 years ago
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    i agree my professor is horrible ):

  10. myininaya
    • 5 years ago
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    did you see my attachment?

  11. anonymous
    • 5 years ago
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    i'm trying to open it, i haven't gotten there yet.

  12. myininaya
    • 5 years ago
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    88*(1+tan(x)^2)^2*tan(x)^2+16*(1+tan(x)^2)^3+16*tan(x)^4*(1+tan(x)^2) is what my friendly computer algebra system got for the 5th derivative

  13. anonymous
    • 5 years ago
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    hah noice

  14. anonymous
    • 5 years ago
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    yeah thats pretty much where i'm at with it ):

  15. anonymous
    • 5 years ago
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    yeah my fifth derivative involves too much product rule.

  16. anonymous
    • 5 years ago
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    i'm working it with someone on chat, and we're keeping everything in terms of tan, its working much easier that way.

  17. myininaya
    • 5 years ago
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    ( think you everything you get a (secx)^2, you are suppose to write it as 1+(tanx)^2

  18. myininaya
    • 5 years ago
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    maybe there is a pattern we havent noticed

  19. anonymous
    • 5 years ago
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    yea i checked my derivatives with your derivatives and it checks but it gets drawn out.

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