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- anonymous

14-10c=94

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- anonymous

14-10c=94

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- anonymous

\[
\begin{align*}
(14-10c) - 14 &= 94 - 14\\
-10c &= 80\\
\frac{-10c}{-10} &= \frac{80}{-10}\\
c &= -8
\end{align*}
\]

- anonymous

how did you put -14 next to 14-10c

- anonymous

I was just showing that I was subtracting 14 from both sides.

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- anonymous

from which

- anonymous

94 and which one

- anonymous

And \(14-10c\).

- anonymous

??????

- anonymous

may you please show me step by step im very confused

- anonymous

So when you have an equation (with an equal sign saying one thing is equivalent to another), in order to preserve the equality, you have to do the same thing ot both sides of the equation.
For example, if you have \(5=5\), if you add \(2\) to both sides, the equality is still preserved:
\[
\begin{align*}
5 &= 5\\
5 + 2 &= 5+2\\
7 &= 7
\end{align*}
\]

- anonymous

So I did the same thing with your equation, except instead of adding two, I subtracted 14.

- anonymous

The thing with my math teacher she wants us to show it step by step

- anonymous

Yeah, so the first step would be subtracting 14 from both sides.

- anonymous

so

- anonymous

14-10c=94
-14 =-14
---------------
-10c=94

- anonymous

?

- anonymous

Well, what's \(94-14\).

- anonymous

so its

- anonymous

14-10c=94
-14 =-14

- anonymous

Well, what I was saying is that the final equation you wrote shouldn't have been \(-10c = 94\), it should be \(-10c = 80\), as \(94-14 = 80\).

- anonymous

oh okay :-) Thankyou !

- anonymous

Glad I could help!

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