anonymous
  • anonymous
14-10c=94
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[ \begin{align*} (14-10c) - 14 &= 94 - 14\\ -10c &= 80\\ \frac{-10c}{-10} &= \frac{80}{-10}\\ c &= -8 \end{align*} \]
anonymous
  • anonymous
how did you put -14 next to 14-10c
anonymous
  • anonymous
I was just showing that I was subtracting 14 from both sides.

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anonymous
  • anonymous
from which
anonymous
  • anonymous
94 and which one
anonymous
  • anonymous
And \(14-10c\).
anonymous
  • anonymous
??????
anonymous
  • anonymous
may you please show me step by step im very confused
anonymous
  • anonymous
So when you have an equation (with an equal sign saying one thing is equivalent to another), in order to preserve the equality, you have to do the same thing ot both sides of the equation. For example, if you have \(5=5\), if you add \(2\) to both sides, the equality is still preserved: \[ \begin{align*} 5 &= 5\\ 5 + 2 &= 5+2\\ 7 &= 7 \end{align*} \]
anonymous
  • anonymous
So I did the same thing with your equation, except instead of adding two, I subtracted 14.
anonymous
  • anonymous
The thing with my math teacher she wants us to show it step by step
anonymous
  • anonymous
Yeah, so the first step would be subtracting 14 from both sides.
anonymous
  • anonymous
so
anonymous
  • anonymous
14-10c=94 -14 =-14 --------------- -10c=94
anonymous
  • anonymous
?
anonymous
  • anonymous
Well, what's \(94-14\).
anonymous
  • anonymous
so its
anonymous
  • anonymous
14-10c=94 -14 =-14
anonymous
  • anonymous
Well, what I was saying is that the final equation you wrote shouldn't have been \(-10c = 94\), it should be \(-10c = 80\), as \(94-14 = 80\).
anonymous
  • anonymous
oh okay :-) Thankyou !
anonymous
  • anonymous
Glad I could help!

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