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anonymous
 5 years ago
1410c=94
anonymous
 5 years ago
1410c=94

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ \begin{align*} (1410c)  14 &= 94  14\\ 10c &= 80\\ \frac{10c}{10} &= \frac{80}{10}\\ c &= 8 \end{align*} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you put 14 next to 1410c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was just showing that I was subtracting 14 from both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0may you please show me step by step im very confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So when you have an equation (with an equal sign saying one thing is equivalent to another), in order to preserve the equality, you have to do the same thing ot both sides of the equation. For example, if you have \(5=5\), if you add \(2\) to both sides, the equality is still preserved: \[ \begin{align*} 5 &= 5\\ 5 + 2 &= 5+2\\ 7 &= 7 \end{align*} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So I did the same thing with your equation, except instead of adding two, I subtracted 14.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The thing with my math teacher she wants us to show it step by step

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, so the first step would be subtracting 14 from both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01410c=94 14 =14  10c=94

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, what's \(9414\).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, what I was saying is that the final equation you wrote shouldn't have been \(10c = 94\), it should be \(10c = 80\), as \(9414 = 80\).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh okay :) Thankyou !
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