anonymous
  • anonymous
ok guys i need help.... how do you do verify this trig identity? cscx (cscx-sinx) + (sinx-cosx)/sinx + cotx = csc squared x
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
myininaya
  • myininaya
split that 2nd fraction into -cotx+cotx=0
anonymous
  • anonymous
ok...
myininaya
  • myininaya
i mean do you see that 2nd fraction beomces 1-cotx and after that we see +cotx

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
wait where did you get the zero?
anonymous
  • anonymous
ok yah haha
anonymous
  • anonymous
thank you for helping me :)
myininaya
  • myininaya
is that all you needed?
anonymous
  • anonymous
after that would what would i do with my cscx (cscx-sinx)?
myininaya
  • myininaya
I got 1/sinx-sinx+1=(1-[sinx]^2+sinx)/sinx=([cosx]^2+sinx)/sinx=[cotx]^2+1=(cscx)^2
myininaya
  • myininaya
oops
anonymous
  • anonymous
cool cool thank you so much is there a way to reward you or something by making me your fan or something?.... what?
myininaya
  • myininaya
fan but I made a mistake
anonymous
  • anonymous
how do i make fan.... and let me look at it ...
myininaya
  • myininaya
do you see become a fan by my name?
anonymous
  • anonymous
nope nothing is by your name
myininaya
  • myininaya
no worries lets just find my mistake
anonymous
  • anonymous
ok
anonymous
  • anonymous
what did you do with the cscx tht was factored out?
myininaya
  • myininaya
1/sinx-sinx+1 (here I found a common denominator) 1/sinx-(sinx)^2/sinx+sinx/sinx
myininaya
  • myininaya
so we have (1-(sinx)^2+sinx)/sinx
anonymous
  • anonymous
ok cool ..... is that all over sinx or just the sin^2 x +sinx?
myininaya
  • myininaya
so we have ([cosx]^2+sinx)/sinx=[cosx]^2/sinx+sinx/sinx=(cosx)^2/sinx+1 BUT (cotx)^2+1=(cscx)^2. IS something missing from your question?
anonymous
  • anonymous
my problem is cscx(cscx-sinx) + (sinx-cosx/sinx) +cotx = csc^2x
anonymous
  • anonymous
so i think thats right ...
myininaya
  • myininaya
omg im stupid i got it let me attach it
anonymous
  • anonymous
it looks right except idk where you got the cos lol
myininaya
  • myininaya
1 Attachment
myininaya
  • myininaya
i dont know either
myininaya
  • myininaya
and we could had done -1+1
myininaya
  • myininaya
I made it way more difficult than it should had been sorry
anonymous
  • anonymous
ok cool thanks i found the become a fan button
anonymous
  • anonymous
and hey it worked out didnt it :P thanks a ton :)
myininaya
  • myininaya
i will be ur fan too
anonymous
  • anonymous
what do you get for having fans?
myininaya
  • myininaya
a new car of course
anonymous
  • anonymous
? a new car? haha what
myininaya
  • myininaya
you get nothing but ego boosts i guess
anonymous
  • anonymous
oh ok haha
anonymous
  • anonymous
i guess it also shows how smart you are :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.