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anonymous

  • 5 years ago

ok guys i need help.... how do you do verify this trig identity? cscx (cscx-sinx) + (sinx-cosx)/sinx + cotx = csc squared x

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  1. myininaya
    • 5 years ago
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    split that 2nd fraction into -cotx+cotx=0

  2. anonymous
    • 5 years ago
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    ok...

  3. myininaya
    • 5 years ago
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    i mean do you see that 2nd fraction beomces 1-cotx and after that we see +cotx

  4. anonymous
    • 5 years ago
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    wait where did you get the zero?

  5. anonymous
    • 5 years ago
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    ok yah haha

  6. anonymous
    • 5 years ago
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    thank you for helping me :)

  7. myininaya
    • 5 years ago
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    is that all you needed?

  8. anonymous
    • 5 years ago
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    after that would what would i do with my cscx (cscx-sinx)?

  9. myininaya
    • 5 years ago
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    I got 1/sinx-sinx+1=(1-[sinx]^2+sinx)/sinx=([cosx]^2+sinx)/sinx=[cotx]^2+1=(cscx)^2

  10. myininaya
    • 5 years ago
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    oops

  11. anonymous
    • 5 years ago
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    cool cool thank you so much is there a way to reward you or something by making me your fan or something?.... what?

  12. myininaya
    • 5 years ago
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    fan but I made a mistake

  13. anonymous
    • 5 years ago
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    how do i make fan.... and let me look at it ...

  14. myininaya
    • 5 years ago
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    do you see become a fan by my name?

  15. anonymous
    • 5 years ago
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    nope nothing is by your name

  16. myininaya
    • 5 years ago
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    no worries lets just find my mistake

  17. anonymous
    • 5 years ago
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    ok

  18. anonymous
    • 5 years ago
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    what did you do with the cscx tht was factored out?

  19. myininaya
    • 5 years ago
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    1/sinx-sinx+1 (here I found a common denominator) 1/sinx-(sinx)^2/sinx+sinx/sinx

  20. myininaya
    • 5 years ago
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    so we have (1-(sinx)^2+sinx)/sinx

  21. anonymous
    • 5 years ago
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    ok cool ..... is that all over sinx or just the sin^2 x +sinx?

  22. myininaya
    • 5 years ago
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    so we have ([cosx]^2+sinx)/sinx=[cosx]^2/sinx+sinx/sinx=(cosx)^2/sinx+1 BUT (cotx)^2+1=(cscx)^2. IS something missing from your question?

  23. anonymous
    • 5 years ago
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    my problem is cscx(cscx-sinx) + (sinx-cosx/sinx) +cotx = csc^2x

  24. anonymous
    • 5 years ago
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    so i think thats right ...

  25. myininaya
    • 5 years ago
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    omg im stupid i got it let me attach it

  26. anonymous
    • 5 years ago
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    it looks right except idk where you got the cos lol

  27. myininaya
    • 5 years ago
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    1 Attachment
  28. myininaya
    • 5 years ago
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    i dont know either

  29. myininaya
    • 5 years ago
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    and we could had done -1+1

  30. myininaya
    • 5 years ago
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    I made it way more difficult than it should had been sorry

  31. anonymous
    • 5 years ago
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    ok cool thanks i found the become a fan button

  32. anonymous
    • 5 years ago
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    and hey it worked out didnt it :P thanks a ton :)

  33. myininaya
    • 5 years ago
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    i will be ur fan too

  34. anonymous
    • 5 years ago
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    what do you get for having fans?

  35. myininaya
    • 5 years ago
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    a new car of course

  36. anonymous
    • 5 years ago
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    ? a new car? haha what

  37. myininaya
    • 5 years ago
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    you get nothing but ego boosts i guess

  38. anonymous
    • 5 years ago
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    oh ok haha

  39. anonymous
    • 5 years ago
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    i guess it also shows how smart you are :)

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