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can you write that properly please using brackets. its really confusing. sorry.
(9/x+2) = (3/x+2) +2x
excellnt. so lets start by taking over the 3/(x+2) because we note that it has the same denom as the other side. so we get ...
(9/x+2) - (3/x+2) = 2x so... from here we subtract the two ...
6/(x+2) = 2x ... now multiply the (x+2) to the other side which will result in ...
6 = 2x(x+2) ... expanding this we will get ...
6 = 2x^2 + 4x ... now bring the 6 over so we will get ...
0 = 2x^2 + 4x - 6 and now factoring out the two for easier solution we get ...
0 = 2 ( x^2 + 2x - 3) and this will factor out to..
0 = 2(x+3)(x-1) soo ...
from here your answer is x+3 = 0 ; hence x = -3
and x - 1 = 0 hence x = 1
So your final answers are x = -3 and 1.
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okay ! I think im getting the hang of it heh thanks. you are a greattt help :DD!
that sounds good. haha npp :)
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