Find the probability that a point X, selected randomly on line LQ, is on the given segment. 1)Line LM 2)line NP 3)line OQ 4)line MQ

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Find the probability that a point X, selected randomly on line LQ, is on the given segment. 1)Line LM 2)line NP 3)line OQ 4)line MQ

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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its upside down sorry about that
The probability would be the ratio of the segment lengths to the total. Let \[S_{AB} = The\ length\ of\ a\ segment\ from\ A\ to\ B\] \[P_{AB} = The\ probability\ for\ a\ random\ point\ to\ be\ on\ the\ segment\ AB\] \[ \rightarrow P_{LM} = S_{LM}/S_{LQ}\] \[ \rightarrow P_{NP} = S_{NP}/S_{LQ}\] \[ \rightarrow P_{OQ} = S_{OQ}/S_{LQ}\] \[ \rightarrow P_{MQ} = S_{MQ}/S_{LQ}\] etc.

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The probability of x being on a line segment is the length of the segment divided by the total length of the line. Which part of this is confusing?
so the first one would be 2/17
Nearly. 2 is the length of LM, but the length of LQ is not 17.
so 2/24
Yes.
Np=12/24 OQ= 12/24 MQ= 19/24
MQ is 22 units in length. Otherwise those numbers are correct.
okay thank you

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