## anonymous 5 years ago find the probability that a randomly chosen point in the figure lies in the shaded region??

1. anonymous

2. anonymous

3. anonymous

4. anonymous

Picture 26 is 9/35 or about 25.7% for the white region and 26/35 or 74.3% for the black region.

5. anonymous

Picture 27 is 1.5625/25 or 6.25% for the white region and 23.4375/25 or 93.75% for the black region.

6. anonymous

7. anonymous

Picture 25: the white area is a semi-circle which has an area of (Pi * radius * radius)/ 2 and the area for the equilateral triangle of (side * side * square root three)/ 4. The black area is $(12.5 * \pi)/(25 * \sqrt{3}) = about90.69%$

8. anonymous

oops... white area is 90.69% and the white area 9.31%. Sorry... I think I am color blind XD.

9. anonymous