anonymous
  • anonymous
find the probability that a randomly chosen point in the figure lies in the shaded region??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
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anonymous
  • anonymous
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anonymous
  • anonymous
Picture 26 is 9/35 or about 25.7% for the white region and 26/35 or 74.3% for the black region.
anonymous
  • anonymous
Picture 27 is 1.5625/25 or 6.25% for the white region and 23.4375/25 or 93.75% for the black region.
anonymous
  • anonymous
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anonymous
  • anonymous
Picture 25: the white area is a semi-circle which has an area of (Pi * radius * radius)/ 2 and the area for the equilateral triangle of (side * side * square root three)/ 4. The black area is \[(12.5 * \pi)/(25 * \sqrt{3}) = about90.69%\]
anonymous
  • anonymous
oops... white area is 90.69% and the white area 9.31%. Sorry... I think I am color blind XD.
anonymous
  • anonymous
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