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anonymous
 5 years ago
charles opened the trunk and found $6750 in $1 bills and $10 bills. If there were 150 more ones than tens, how many of each kind were there?
anonymous
 5 years ago
charles opened the trunk and found $6750 in $1 bills and $10 bills. If there were 150 more ones than tens, how many of each kind were there?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let\[n_1, n_{10}\]be the number of $1 and $10 bills respectively. You know that\[n_1=n_{10}+150\]since the number of 1s is 150 more than the number of 10s. You also know\[6750=n_1$1+n_{10}$10\]that is\[6750=n_1+10n_{10}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sub. the expression for n_1 into the second equation to find\[6750=(n_{10}+150)+10n_{10}=11n_{10}+150\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then\[n_{10}=\frac{6750150}{11}=600\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are 600 $10 bills. So the number of $1s is,\[n_1=675010 \times 600=750\]
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