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chelbell409

  • 3 years ago

charles opened the trunk and found $6750 in $1 bills and $10 bills. If there were 150 more ones than tens, how many of each kind were there?

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  1. lokisan
    • 3 years ago
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    Let\[n_1, n_{10}\]be the number of $1 and $10 bills respectively. You know that\[n_1=n_{10}+150\]since the number of 1s is 150 more than the number of 10s. You also know\[6750=n_1$1+n_{10}$10\]that is\[6750=n_1+10n_{10}\]

  2. lokisan
    • 3 years ago
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    Sub. the expression for n_1 into the second equation to find\[6750=(n_{10}+150)+10n_{10}=11n_{10}+150\]

  3. lokisan
    • 3 years ago
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    Then\[n_{10}=\frac{6750-150}{11}=600\]

  4. lokisan
    • 3 years ago
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    There are 600 $10 bills. So the number of $1s is,\[n_1=6750-10 \times 600=750\]

  5. chelbell409
    • 3 years ago
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    thanks so very much

  6. lokisan
    • 3 years ago
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    No probs :)

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