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anonymous

  • 5 years ago

An antiderivative for (1/(x²-2x+2)) is would really appreciate help with this I know it is rewritten (x²-2x+2)^-1 but where do I go from there?

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  1. anonymous
    • 5 years ago
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    Look up "Integration by Partial Fractions" - break 1/(x^2-2x+2) into two separate fractions added together, and evaluate those; usually with the natural logarithm. http://www.intmath.com/Methods-integration/11_Integration-partial-fractions.php

  2. anonymous
    • 5 years ago
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    I'm taking Ap Calculus AB and our course doesn't cover this material. Is there any other way to do it?

  3. anonymous
    • 5 years ago
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    I'm pretty sure there's no other way to do it. :/ Seriously though, learning partial fractions helps MAJORLY.

  4. anonymous
    • 5 years ago
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    ...and I'm pretty sure that it's a topic on the AB exam, so you'll probably want to know it anyway..

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