## anonymous 5 years ago charles opened the trunk and found $6750 in$1 bills and \$10 bills. If there were 150 more ones than tens, how many of each kind were there?

1. anonymous

You need to set up a system of equations here. As you're looking for the number of each kind of bill, we'll make a variable for each kind: let $$o$$ be the number of ones, and $$t$$ be the number of tens. First, we know that together they make $$6750$$. Second, we know how many more ones there are then tens: \begin{align} o + 10t = 6750\\ o + 150 = t\\ \end{align} Now all you need to do is solve the system for $$o$$ and $$t$$.

2. anonymous

let the 10s be x while 1s be y 10x+y=6750 11x=6600 + x-y=150 x=600, y=450