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anonymous

  • 5 years ago

I have to add the following z/z^2-49 + 2/z+7

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  1. anonymous
    • 5 years ago
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    \[\frac{z}{z^2}-49+\frac{2}{z}+7=\frac{1}{z}-49+\frac{2}{z}+7=\frac{3}{z}-42\]

  2. anonymous
    • 5 years ago
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    actually I should of wrote it out as z/(z^2-49) + 2/(z+7), does that make the answer different??

  3. anonymous
    • 5 years ago
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    yes, it does

  4. anonymous
    • 5 years ago
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    start w a common denom of (z+7) (z-7)

  5. anonymous
    • 5 years ago
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    thats about as far as I got!!

  6. anonymous
    • 5 years ago
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    z+2(z-7) all over (z+7)(z-7)

  7. anonymous
    • 5 years ago
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    then the z-7 cancels out, right??

  8. anonymous
    • 5 years ago
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    z+2z-7 -------- z^2-49

  9. anonymous
    • 5 years ago
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    So is that the answer??

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spraguer (Moderator)
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