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anonymous

  • 5 years ago

- FOR QUANTAM MODULUS! OTHERS ARE ALSO WELCOME TO ANSWER! Find the values of the trigonometric functions of t from the given information. Sin(t)= Cos(t)= Csc(t)= Sec(t)= Cot(t)=

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  1. anonymous
    • 5 years ago
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    Forgot to put the main part. tan(t) = -2, csc(t) > 0

  2. anonymous
    • 5 years ago
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    Exact value?

  3. anonymous
    • 5 years ago
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    That's all it gives.

  4. anonymous
    • 5 years ago
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    This is tricky, mainly because there is no exact angle that you can reference for tan(t)=-2..

  5. anonymous
    • 5 years ago
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    That's what I thought.

  6. anonymous
    • 5 years ago
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    Is there a way to solve it?

  7. anonymous
    • 5 years ago
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    There is, but I can't quite see it. :/ I'm trying..

  8. anonymous
    • 5 years ago
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    Take your time. Thanks.

  9. anonymous
    • 5 years ago
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    Alright, well we can say that t = arctan(-2). Numerically, from a calculator this is about -1.1071 radians, and you can plug it into the other trig functions to get the values. :/ Sorry, but there is no exact form of t.

  10. anonymous
    • 5 years ago
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    NP, Thank for your help.

  11. anonymous
    • 5 years ago
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    You're quite welcome, glad to do it.

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spraguer (Moderator)
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