anonymous
  • anonymous
- FOR QUANTAM MODULUS! OTHERS ARE ALSO WELCOME TO ANSWER! Find the values of the trigonometric functions of t from the given information. Sin(t)= Cos(t)= Csc(t)= Sec(t)= Cot(t)=
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Forgot to put the main part. tan(t) = -2, csc(t) > 0
anonymous
  • anonymous
Exact value?
anonymous
  • anonymous
That's all it gives.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
This is tricky, mainly because there is no exact angle that you can reference for tan(t)=-2..
anonymous
  • anonymous
That's what I thought.
anonymous
  • anonymous
Is there a way to solve it?
anonymous
  • anonymous
There is, but I can't quite see it. :/ I'm trying..
anonymous
  • anonymous
Take your time. Thanks.
anonymous
  • anonymous
Alright, well we can say that t = arctan(-2). Numerically, from a calculator this is about -1.1071 radians, and you can plug it into the other trig functions to get the values. :/ Sorry, but there is no exact form of t.
anonymous
  • anonymous
NP, Thank for your help.
anonymous
  • anonymous
You're quite welcome, glad to do it.

Looking for something else?

Not the answer you are looking for? Search for more explanations.