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chelbell409

solve -81+4x^2=0 by factoring

  • 3 years ago
  • 3 years ago

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  1. abhorsen
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    Remember the rule about factoring differences of squares: \(a^2-b^2 = (a+b)(a-b)\). Does that help you out?

    • 3 years ago
  2. chelbell409
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    no can u explain it farther

    • 3 years ago
  3. abhorsen
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    So are the two parts of the equation (\(81\) and \(4x^2\)) squares?

    • 3 years ago
  4. chelbell409
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    ok

    • 3 years ago
  5. abhorsen
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    Now set \(a=4x^2\) and \(b=81\), and plug it in to the equation I gave above.

    • 3 years ago
  6. abhorsen
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    Uh... correction: \(a^2 = 4x^2\) and \(b^2 = 81\).

    • 3 years ago
  7. Kynosis
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    Yep. (2x - 9) (2x + 9)

    • 3 years ago
  8. quannie74
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    \[-81+4x^2=0\]

    • 3 years ago
  9. quannie74
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    can u explain step by step because i am on these problems in my math class

    • 3 years ago
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