Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

chelbell409

  • 5 years ago

solve -81+4x^2=0 by factoring

  • This Question is Closed
  1. abhorsen
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Remember the rule about factoring differences of squares: \(a^2-b^2 = (a+b)(a-b)\). Does that help you out?

  2. chelbell409
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no can u explain it farther

  3. abhorsen
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So are the two parts of the equation (\(81\) and \(4x^2\)) squares?

  4. chelbell409
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

  5. abhorsen
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Now set \(a=4x^2\) and \(b=81\), and plug it in to the equation I gave above.

  6. abhorsen
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Uh... correction: \(a^2 = 4x^2\) and \(b^2 = 81\).

  7. Kynosis
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yep. (2x - 9) (2x + 9)

  8. quannie74
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[-81+4x^2=0\]

  9. quannie74
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can u explain step by step because i am on these problems in my math class

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy