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chelbell409
 4 years ago
solve 81+4x^2=0 by factoring
chelbell409
 4 years ago
solve 81+4x^2=0 by factoring

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abhorsen
 4 years ago
Best ResponseYou've already chosen the best response.0Remember the rule about factoring differences of squares: \(a^2b^2 = (a+b)(ab)\). Does that help you out?

chelbell409
 4 years ago
Best ResponseYou've already chosen the best response.0no can u explain it farther

abhorsen
 4 years ago
Best ResponseYou've already chosen the best response.0So are the two parts of the equation (\(81\) and \(4x^2\)) squares?

abhorsen
 4 years ago
Best ResponseYou've already chosen the best response.0Now set \(a=4x^2\) and \(b=81\), and plug it in to the equation I gave above.

abhorsen
 4 years ago
Best ResponseYou've already chosen the best response.0Uh... correction: \(a^2 = 4x^2\) and \(b^2 = 81\).

quannie74
 4 years ago
Best ResponseYou've already chosen the best response.0can u explain step by step because i am on these problems in my math class
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