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anonymous

  • 5 years ago

can someone help show me how this is true... u'(t) = -sin^2(t)/cos(t) = -sect + cost

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  1. myininaya
    • 5 years ago
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    ?

  2. myininaya
    • 5 years ago
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    I don't think I understand what your asking. Are you asking does -(sint)^2/cost simplify to -sect+cost

  3. anonymous
    • 5 years ago
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    yes

  4. myininaya
    • 5 years ago
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    I honestly don't think it does equal

  5. anonymous
    • 5 years ago
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    thats how i feel, it is in the solution manual and in order to get the same answer I need to convince myself that it is true...

  6. myininaya
    • 5 years ago
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    what happens if you plug zero in on both sides? the equation doesn't hold

  7. myininaya
    • 5 years ago
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    oops it does hold for t=0

  8. myininaya
    • 5 years ago
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    let me think some more

  9. myininaya
    • 5 years ago
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    omg im moron i got it

  10. anonymous
    • 5 years ago
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    yahh!

  11. myininaya
    • 5 years ago
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    okay (sint)^2+(cost)^2=1 so (sint)^2=1-(cost)^2 therefore -(sint)^2=(cost)^2-1 => -(sint)^2/cost=[(cost)^2-1]/cost

  12. myininaya
    • 5 years ago
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    split those fractions up! :)

  13. myininaya
    • 5 years ago
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    so we have (cost)^2/cost - 1/cost= cost-sect= -sect+cost

  14. myininaya
    • 5 years ago
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    any questions? :)

  15. anonymous
    • 5 years ago
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    good eye thanks!

  16. myininaya
    • 5 years ago
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    sometimes im so slow

  17. anonymous
    • 5 years ago
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    haha saved me a headache

  18. anonymous
    • 5 years ago
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    :)

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