can someone help show me how this is true... u'(t) = -sin^2(t)/cos(t) = -sect + cost

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can someone help show me how this is true... u'(t) = -sin^2(t)/cos(t) = -sect + cost

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I don't think I understand what your asking. Are you asking does -(sint)^2/cost simplify to -sect+cost
yes

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I honestly don't think it does equal
thats how i feel, it is in the solution manual and in order to get the same answer I need to convince myself that it is true...
what happens if you plug zero in on both sides? the equation doesn't hold
oops it does hold for t=0
let me think some more
omg im moron i got it
yahh!
okay (sint)^2+(cost)^2=1 so (sint)^2=1-(cost)^2 therefore -(sint)^2=(cost)^2-1 => -(sint)^2/cost=[(cost)^2-1]/cost
split those fractions up! :)
so we have (cost)^2/cost - 1/cost= cost-sect= -sect+cost
any questions? :)
good eye thanks!
sometimes im so slow
haha saved me a headache
:)

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