anonymous
  • anonymous
can someone help show me how this is true... u'(t) = -sin^2(t)/cos(t) = -sect + cost
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
myininaya
  • myininaya
?
myininaya
  • myininaya
I don't think I understand what your asking. Are you asking does -(sint)^2/cost simplify to -sect+cost
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

myininaya
  • myininaya
I honestly don't think it does equal
anonymous
  • anonymous
thats how i feel, it is in the solution manual and in order to get the same answer I need to convince myself that it is true...
myininaya
  • myininaya
what happens if you plug zero in on both sides? the equation doesn't hold
myininaya
  • myininaya
oops it does hold for t=0
myininaya
  • myininaya
let me think some more
myininaya
  • myininaya
omg im moron i got it
anonymous
  • anonymous
yahh!
myininaya
  • myininaya
okay (sint)^2+(cost)^2=1 so (sint)^2=1-(cost)^2 therefore -(sint)^2=(cost)^2-1 => -(sint)^2/cost=[(cost)^2-1]/cost
myininaya
  • myininaya
split those fractions up! :)
myininaya
  • myininaya
so we have (cost)^2/cost - 1/cost= cost-sect= -sect+cost
myininaya
  • myininaya
any questions? :)
anonymous
  • anonymous
good eye thanks!
myininaya
  • myininaya
sometimes im so slow
anonymous
  • anonymous
haha saved me a headache
anonymous
  • anonymous
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.