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anonymous
 5 years ago
can someone help show me how this is true...
u'(t) = sin^2(t)/cos(t) = sect + cost
anonymous
 5 years ago
can someone help show me how this is true... u'(t) = sin^2(t)/cos(t) = sect + cost

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0I don't think I understand what your asking. Are you asking does (sint)^2/cost simplify to sect+cost

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0I honestly don't think it does equal

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats how i feel, it is in the solution manual and in order to get the same answer I need to convince myself that it is true...

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0what happens if you plug zero in on both sides? the equation doesn't hold

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0oops it does hold for t=0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0let me think some more

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0omg im moron i got it

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0okay (sint)^2+(cost)^2=1 so (sint)^2=1(cost)^2 therefore (sint)^2=(cost)^21 => (sint)^2/cost=[(cost)^21]/cost

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0split those fractions up! :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we have (cost)^2/cost  1/cost= costsect= sect+cost

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha saved me a headache
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