A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

I have been stuck on this question for like an hour z/(z^2-49) + 2/(z+7). Someone help please!!

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so what happens is this .... you take the fraction to the other side.. z/(z^2-49) = -2/(z+7) now you can factorize z^2-49 = (z+7)(z-7) so we get z/(z+7)(z-7) = -2/(z+7) now you multiply (z+7) on both sides so we get z/(z-7) = -2 this ends up being ... z = -2(z-7) z = -2z + 14 z+2z = 14 3z = 14 z = 14/3 so the final answer is z = 14/3

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, I think I got it!! Thank you so much!!

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    np :)

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    There is no equation, therefore you do not get an answer. You are adding two fractions, so you must get a common denominator. Z^2 - 49 factors into (z - 7)(z + 7) The other denominator is (z+7) So both denominators need to be (z-7)(z+7) so you need to multiply the second fraction by (z-7)/(z-7) So you have (2(z-7))/(z+7)(z-7) which is (2z - 14)/(z + 7)(z - 7) Now you have two fractions with a common denominator so you are ready to add. z/((z + 7)(z - 7) + (2z - 14)/(z + 7)(z - 7) = (3z - 14)/((z + 7)(z - 7)

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.