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anonymous

  • 5 years ago

what are the critical points for F(x) = -2*(x^2+1)/(x^2-1)^2

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  1. anonymous
    • 5 years ago
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    Agh. D: This one's messy. Get some quotient rule & chain rule in there, take the derivative and set it equal to zero. Keep the -2 on the outside the whole time, for simplicity.

  2. myininaya
    • 5 years ago
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    also find where f' doesnt exist

  3. anonymous
    • 5 years ago
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    dy^2/d^2x -2/(x^2-1) = dy/dx(4x)/(x^2-1) = (-12x^3-4)/(x^2 - 1)^3 set dy^2/d^2x to zero which equal

  4. anonymous
    • 5 years ago
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    Ah yes, and the second derivative as well. Points of inflection. :P

  5. anonymous
    • 5 years ago
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    wait oops.... i was look for the point of inflection sorry. So.....dy/dx -2/(x^2-1) = (4x)/(x^2-1) set the derivative to zero and solve. the first derivative is 0.

  6. anonymous
    • 5 years ago
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    there isn't a point of inflection because it is a monotonic function

  7. anonymous
    • 5 years ago
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    You're correct, my bad. :P Got me confused for a second there.

  8. anonymous
    • 5 years ago
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    complicated

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