anonymous
  • anonymous
Find the surface area of a sphere of radius r, using calculus.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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myininaya
  • myininaya
omg i know this
myininaya
  • myininaya
give me just a sec
anonymous
  • anonymous
that would be amazing if you could help! :)

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myininaya
  • myininaya
so the equation of a circle having center (0,0) is x^2+y^2+r^2
myininaya
  • myininaya
oh surface area not volume one sec. let me rething my strategy
anonymous
  • anonymous
ok. thanks
anonymous
  • anonymous
Use the formula for the surface area of a general equation revolved around the x-axis. If you start with x^2 + y^2 = r^2, and your function is y, then f(x) = sqrt(r^2-x^2). The formula for the surface area of revolution is, in this case, \[SA = 2 \pi* \int\limits_{-r}^{r} \ \ f(x) * \sqrt{1+f(x)^2}\] Integrate and simplify.
anonymous
  • anonymous
Sorry, inside the root of the integrand it should be f'(x)^2.
myininaya
  • myininaya
what is the circumference of sphere
anonymous
  • anonymous
Thanks QuantumModulus, that helped a lot!!
anonymous
  • anonymous
Glad to help. :)
myininaya
  • myininaya
have you done trig substition yet?
myininaya
  • myininaya
I think you may have to do in one of the steps
myininaya
  • myininaya
nvm it is a simple integration
myininaya
  • myininaya
1 Attachment
myininaya
  • myininaya
ok but i think was suppose to get 4pi*r^2
myininaya
  • myininaya
let me know what you get?
myininaya
  • myininaya
ok it is 4*pi*r^2 because the semicirlce is being revolved about the x axis
myininaya
  • myininaya
Yes! :)
myininaya
  • myininaya
ignore the extra stuff on that attachment
myininaya
  • myininaya
I have to go. You can check your work with the attachment just ignore the But part. goodnight

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