the function f is defined for all real numbers x by f(x) = ax^2 + bx + c where a, b and c are constants and a is negative. in the xy-plane, the x-coordinate of the vertex of the parabola y =f(x) is -1. If t is a real number for which f(t) > f(0), which of the following must be true.
1: -2 < t < 0
2: f(t) < f(-2)
3: f(t) > f(1)
really struggling to conceptualize this...

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are you agree?

yes, but i thought the value of c caused a vertical shift?

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