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just set up a simple algebra equation. you have one unknown: linda's age. we'll call this x. \[3*x - 36 = 2*x\] do you know how to solve from here?
That's exactly what I got and Im having a hard time trying to solve this!
so the trick here is to get all your variables on one side. get the x's on the left and everything else on the right. then combine like terms: 3*x - 2*x = 36 1*x = 36 your answer!
3x-6=2x 3x-2x=6 x(3-2)=6 x=6/(3-2)=6
you need to isolate the variable which is x
WHoa, sorry abouit that-went too fast. Should be x(3-2)=36 which of course is x=36
It's a typo on my part. I typed 6 when I'd meant to type 36.
So the steps should be: 3x-36=2x 3x-2x=36 x(3-2)=36 x=6/(3-2) x=6
Oh, ok! Thanks guys! I think I got it! I have to show work too! But i understand now! Damn, Linda's old! LOL!
Don't just copy what I've shown here. Understand it. WOork through it backwards. Otherwise on exam day, you'll be hosed. Cheers.
36 isn't very old :)
I know! LOL! Just a corney joke! Ya know what, that's the exact answer I got before, but when i went to check it, it didnt come out right! Could you help me check the answer, please?
What is it that you don't understand? To check the answer, I would go back to the original problem statement and see if my solution holds true. So let's test if my solution of L=36 is true. If three times Linda's age is decreased by 36, the result is twice Linda's age. How old is Linda??? Then is this statement true: 3L-36 = 2L 3*36-36 = 2*36.............substitute L=36 36(3-1) = 2*36...............factor 36 out 3-1 = 2...........................divide both sides by 36 2=2.................................identity. Therefore, the solution is valid.
Sorry, I magically switched from using x as my variable to using L as my variable. It really doesn't matter--a duck by any other name is still a duck--as long as you can keep it all straight on paper or in your head. :)