anonymous
  • anonymous
Find the amplitude and period of the function? -5sin(4pix)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
So a general formula for a periodic function is as follows: \[ A\sin{2\pi f x} \] Where \(|A|\) will be the amplitude, and \(f\) will be the frequency, which is one over the period (\(P=\frac{1}{f}\)).
anonymous
  • anonymous
Can you get the answer from that?
anonymous
  • anonymous
I don't understand the P=1/f part?

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anonymous
  • anonymous
Well, P is the period. And \(f\) is the frequency. That's just saying the reciprocal of the frequency is the period.
anonymous
  • anonymous
In the argument of your function you have 4*Pi*x. Your objective should be to make this match the form of 2*Pi*f*x. Then, your F is the denominator of your P=1/f.
anonymous
  • anonymous
Ok, Thanks. One more y= 7sin (1/2(x+pi/3))
anonymous
  • anonymous
Well, a more general form of the equation is: \[ A\sin(2\pi f x + \phi) \] This means all you have to do is multiply out the things inside the parentheses, and then fit them to find what your \(f\) is.

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