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anonymous

  • 5 years ago

Find the amplitude, period, and phase shift of the function? y= 8sin(5/6x-pi/5)

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  1. anonymous
    • 5 years ago
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    we know that the general formula is the following:\[y = A*\sin(\omega t +\theta)\]

  2. anonymous
    • 5 years ago
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    so in this case we can compute the following: - A = 8 -\[\theta\] (phase shift) = pi/5 - w = 5/6 (t)

  3. anonymous
    • 5 years ago
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    I forgot what w = ? to really, but if you have te formula for w, then you can computer t ^_^

  4. anonymous
    • 5 years ago
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    the*

  5. anonymous
    • 5 years ago
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    compute*

  6. anonymous
    • 5 years ago
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    \(\omega = 2\pi f\) where \(f\) is the reciprocal of the period.

  7. anonymous
    • 5 years ago
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    thank you abhorsen ^_^

  8. anonymous
    • 5 years ago
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    No problem :)

  9. anonymous
    • 5 years ago
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    so in this case:\[T= 2\pi / w = 2\pi /5/6 = 7.5\] Correct me if I'm wrong

  10. anonymous
    • 5 years ago
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    T= 7.5 secs

  11. anonymous
    • 5 years ago
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    wait I forgot f lol

  12. anonymous
    • 5 years ago
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    nvm F ^^"

  13. anonymous
    • 5 years ago
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    Final Answer: - A = 8 - phase angle = pi/5 - T = 7.5 secs

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