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anonymous
 5 years ago
Find the amplitude, period, and phase shift of the function?
y= 8sin(5/6xpi/5)
anonymous
 5 years ago
Find the amplitude, period, and phase shift of the function? y= 8sin(5/6xpi/5)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we know that the general formula is the following:\[y = A*\sin(\omega t +\theta)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in this case we can compute the following:  A = 8 \[\theta\] (phase shift) = pi/5  w = 5/6 (t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I forgot what w = ? to really, but if you have te formula for w, then you can computer t ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\(\omega = 2\pi f\) where \(f\) is the reciprocal of the period.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you abhorsen ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so in this case:\[T= 2\pi / w = 2\pi /5/6 = 7.5\] Correct me if I'm wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Final Answer:  A = 8  phase angle = pi/5  T = 7.5 secs
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