anonymous
  • anonymous
Find the amplitude, period, and phase shift of the function? y= 8sin(5/6x-pi/5)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
we know that the general formula is the following:\[y = A*\sin(\omega t +\theta)\]
anonymous
  • anonymous
so in this case we can compute the following: - A = 8 -\[\theta\] (phase shift) = pi/5 - w = 5/6 (t)
anonymous
  • anonymous
I forgot what w = ? to really, but if you have te formula for w, then you can computer t ^_^

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anonymous
  • anonymous
the*
anonymous
  • anonymous
compute*
anonymous
  • anonymous
\(\omega = 2\pi f\) where \(f\) is the reciprocal of the period.
anonymous
  • anonymous
thank you abhorsen ^_^
anonymous
  • anonymous
No problem :)
anonymous
  • anonymous
so in this case:\[T= 2\pi / w = 2\pi /5/6 = 7.5\] Correct me if I'm wrong
anonymous
  • anonymous
T= 7.5 secs
anonymous
  • anonymous
wait I forgot f lol
anonymous
  • anonymous
nvm F ^^"
anonymous
  • anonymous
Final Answer: - A = 8 - phase angle = pi/5 - T = 7.5 secs

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