## anonymous 5 years ago Find the amplitude, period, and phase shift of the function? y= 8sin(5/6x-pi/5)

1. anonymous

we know that the general formula is the following:$y = A*\sin(\omega t +\theta)$

2. anonymous

so in this case we can compute the following: - A = 8 -$\theta$ (phase shift) = pi/5 - w = 5/6 (t)

3. anonymous

I forgot what w = ? to really, but if you have te formula for w, then you can computer t ^_^

4. anonymous

the*

5. anonymous

compute*

6. anonymous

$$\omega = 2\pi f$$ where $$f$$ is the reciprocal of the period.

7. anonymous

thank you abhorsen ^_^

8. anonymous

No problem :)

9. anonymous

so in this case:$T= 2\pi / w = 2\pi /5/6 = 7.5$ Correct me if I'm wrong

10. anonymous

T= 7.5 secs

11. anonymous

wait I forgot f lol

12. anonymous

nvm F ^^"

13. anonymous

Final Answer: - A = 8 - phase angle = pi/5 - T = 7.5 secs