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anonymous

  • 5 years ago

needing help on implicit differentiations?

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  1. anonymous
    • 5 years ago
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    i can help

  2. anonymous
    • 5 years ago
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    Really!

  3. anonymous
    • 5 years ago
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    Can i write the equation down and you show me step by step how to do it?

  4. anonymous
    • 5 years ago
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    Yes

  5. anonymous
    • 5 years ago
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    okay this is the instructions...Use implicit differentiation to find the value of dy/dx at the indicated point. e^y+2y=3x-5 ; at the point (2,0)

  6. anonymous
    • 5 years ago
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    (dy/dx)e^y + 2dy/dx = 3 dy/dx(e^y + 2) = 3 (dy/dx)= 3/(e^y + 2) plug in the value of x an y in the equation but there isn't a y varible ( dy/dx)= 3/(e^0 + 2) ( dy/dx)= 3/3 = 1

  7. anonymous
    • 5 years ago
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    remember dy/dx e^(f(x)) = f'(x)e^(f(x))

  8. anonymous
    • 5 years ago
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    okay so on the first line why are you taking out the Y in 2y?

  9. anonymous
    • 5 years ago
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    oh are you taking y'

  10. anonymous
    • 5 years ago
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    implicate differentiate is all about in term of a variable and the variable in this problem is x. So differentiate the polynomials and if DOESNT have x in the polynomial then add dy/dx to the polynomial

  11. anonymous
    • 5 years ago
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    implicit*

  12. anonymous
    • 5 years ago
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    for example d/dx 3 y^3 = 9 y ^2 dy/dx

  13. anonymous
    • 5 years ago
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    oh okay. can you help me on another one? i am trying to correct a test and want to make sure i understand this before i attempt the next homework

  14. anonymous
    • 5 years ago
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    sure

  15. anonymous
    • 5 years ago
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    awesome here it is. Again thank you so much. I am in college and math is not my thing.

  16. anonymous
    • 5 years ago
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    awesome here it is. Again thank you so much. I am in college and math is not my thing. xy-2x=y ^{2} - 4 ; at the point (5,3)

  17. anonymous
    • 5 years ago
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    xy-2x=y ^{2} - 4 ; at the point (5,3) xdy/dx + y - 2 = 2ydy/dx /// remember the multiplication rule dy/dx(2y - x)= y-2 dy/dx= (y-2)/((2y - x)) plug in values (3-1)/(6-5)= 2

  18. anonymous
    • 5 years ago
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    3-1?

  19. anonymous
    • 5 years ago
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    was that a typeo shouldnt it be 3-2/6-5=1?

  20. anonymous
    • 5 years ago
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    or am i thinking wrong?

  21. anonymous
    • 5 years ago
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    oops yep 1

  22. anonymous
    • 5 years ago
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    oh good i was hoping i was starting to understand. could you help me correct the rest of my test?

  23. anonymous
    • 5 years ago
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    (3-2)/(6-5)=1

  24. anonymous
    • 5 years ago
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    sure

  25. anonymous
    • 5 years ago
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    okay the next one i only got one point off but i am not really sure why here is the problem

  26. anonymous
    • 5 years ago
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    a women standing on a cliff is watching a motorboat through a telescope as the boat travels away from the base of the cliff. The telescope is 250 feet above the water level and the boat is traveling at a speed of 20 feet per second. How fast is the distance between the woman and the boat increasing at the moment when the boat is 600 feet from away?

  27. anonymous
    • 5 years ago
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    here is what i did x^2 + 250^2 = z^2 2x + 0 = 2z 2x dx/dt = 2z dx/dt 600dx/dt=650(+20) dx/dt = 21.7 ft/s

  28. anonymous
    • 5 years ago
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    The boat and the women are in a triangle formation. So \[x^2 +y^2 = z^2\] implicit differentiate in terms of time. so \[(x) dx/dt + (y) dy/dt = (z) dz/dt\] where x= the distance the boat is and dx/dt the rate of the boat moving away. because the women is sationary the women's dy/dt is 0.

  29. anonymous
    • 5 years ago
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    she circled the +20 and put an arrow to the dx/dt

  30. anonymous
    • 5 years ago
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    So (x)dx/dt=(z)dz/dt 600* 20 = z dz/dt we are trying to find dz/dt but we don't have z x^2+y^2=z^2 600^2 + 250^2 = z^2 z=650

  31. anonymous
    • 5 years ago
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    oh okay i am with you now.

  32. anonymous
    • 5 years ago
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    600* 20 = 650 dz/dt dz/dt = 18.46

  33. anonymous
    • 5 years ago
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    sorry the computer is slow today

  34. anonymous
    • 5 years ago
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    no it is okay i am just so greatful for the help

  35. anonymous
    • 5 years ago
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    :)

  36. anonymous
    • 5 years ago
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    wow 20 is the answer.... what did the teacher want an extimate

  37. anonymous
    • 5 years ago
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    idk maybe she only counted one off because i worked it mostly right just got the ending off

  38. anonymous
    • 5 years ago
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    okay ready for the next one? just to warn you i have like 11 left i need help on, but they get easier i think..lol

  39. anonymous
    • 5 years ago
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    lol ok

  40. anonymous
    • 5 years ago
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    okay so i had this idea so i dont have to type out all this and stuff i would just attach a file

  41. anonymous
    • 5 years ago
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    that would be better

  42. anonymous
    • 5 years ago
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    i am working on it give me a minute or so

  43. anonymous
    • 5 years ago
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    here is the next page

  44. anonymous
    • 5 years ago
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    1 Attachment
  45. anonymous
    • 5 years ago
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    here is page 2

  46. anonymous
    • 5 years ago
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    1 Attachment
  47. anonymous
    • 5 years ago
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    here is the last page

  48. anonymous
    • 5 years ago
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    1 Attachment
  49. anonymous
    • 5 years ago
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    did they come in?

  50. anonymous
    • 5 years ago
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    lol I need to download the new adobe sofeware

  51. anonymous
    • 5 years ago
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    ha ha ha could you please

  52. anonymous
    • 5 years ago
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    no can't see them

  53. anonymous
    • 5 years ago
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    okay try this one

  54. anonymous
    • 5 years ago
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    1 Attachment
  55. anonymous
    • 5 years ago
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    1 Attachment
  56. anonymous
    • 5 years ago
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    1 Attachment
  57. anonymous
    • 5 years ago
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    is that better

  58. anonymous
    • 5 years ago
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    NO cant read it don't know why

  59. anonymous
    • 5 years ago
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    did you check the ones i just put up their in word

  60. anonymous
    • 5 years ago
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    what microsoft word do you have?

  61. anonymous
    • 5 years ago
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    because i can save it in a different format

  62. anonymous
    • 5 years ago
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    try this

    1 Attachment
  63. anonymous
    • 5 years ago
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    it worked

  64. anonymous
    • 5 years ago
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    okay awesome here come the rest

  65. anonymous
    • 5 years ago
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  66. anonymous
    • 5 years ago
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    1 Attachment
  67. anonymous
    • 5 years ago
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    the order is 10,20,30

  68. anonymous
    • 5 years ago
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    okay could we just go step by step and explain what i did wrong?

  69. anonymous
    • 5 years ago
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    or is that too much?

  70. anonymous
    • 5 years ago
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    number 17: 2x^3+ 3x^2 = 2 = f(x) 12x^2 + 6x = f'(x) = 0 at x =-1/2 and x= 0 24x+ 6 = f''(x) = 0 at -1/4

  71. anonymous
    • 5 years ago
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    awesome could we start at number 12 though

  72. anonymous
    • 5 years ago
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    increasing [-∞. -1/2][0, ∞] decreasing [-1/4,-1/2] local/absolute maximum when f'(x) = 0 and f''(x) < 0 at x=-1/2 local/absolute minimum when f'(x) = 0 and f''(x) > 0 at x=0

  73. anonymous
    • 5 years ago
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    is that for 17?

  74. anonymous
    • 5 years ago
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    yeah

  75. anonymous
    • 5 years ago
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    thank you so much

  76. anonymous
    • 5 years ago
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    find the intervals of decreasing and increasing take the derivative and set it to zero. the number plug it in the ORIGINAL f(x) and if the number is negative the between the local max or min it is decreasing and whent he number is positive between the local max or min it is increasing

  77. anonymous
    • 5 years ago
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    okay tht makes since

  78. anonymous
    • 5 years ago
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    to find the local max and min.... find f''(x) and plug in the f'(x) number and if it is negative (positive) it is a local maximum(minimum). of the local max and min plug them in the original f(x) AND which ever the local max or min is the most positive or negative is the absolute max or min respectively.

  79. anonymous
    • 5 years ago
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    find the point of inflection.. f''(x) to zero and solve

  80. anonymous
    • 5 years ago
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    going to bed I will help tomorrow if you need it?

  81. anonymous
    • 5 years ago
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    okay how can i get a hold of you

  82. anonymous
    • 5 years ago
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    i will post more ....you just log on. when do you need to hand it in?

  83. anonymous
    • 5 years ago
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    by next monday but i have 5 more sections of homework i need to do also for the next sections

  84. anonymous
    • 5 years ago
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    could i get help with those if needed? i can work on them tomorrow and then ask for help

  85. anonymous
    • 5 years ago
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    ok

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is replying to Can someone tell me what button the professor is hitting...

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