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anonymous
 5 years ago
Suppose that the width of a certain rectangle is 8 inches less than its length. The area is numerically 7 less than twice the perimeter. Find the length and width of the rectangle
anonymous
 5 years ago
Suppose that the width of a certain rectangle is 8 inches less than its length. The area is numerically 7 less than twice the perimeter. Find the length and width of the rectangle

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know that w = l  8 and that l*w = 2*2*(l + w)  7 plugging in the first equation into the second, you get l^2  8*l = 8*l  23 or l^2  16*l + 39 = 0 which factors into (l  13)(l3) = 0 or l = 3,13. Therefore l = 13, w = 5
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