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anonymous

  • 5 years ago

a pool measuring 14 meters by 24 meters is surrounded by a path of uniform width. if the area of the pool and path combined is 1496meters wha tis the width of the path?

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  1. anonymous
    • 5 years ago
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    since you have the total area of the pool and the path combined, and enough information to find the area of the pool, a good place to start this problem would be to find the area of the pool and subtract it from the total area to find the area of the path.

  2. anonymous
    • 5 years ago
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    from here it might be helpful to draw a diagram, a small rectangle (the pool) inside a large rectangle (the surrounding path).

  3. anonymous
    • 5 years ago
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    label the measurements that you know along the sides of the pool, and call the width of the path x. this would make one side 14+2x and the other side 24+2x.

  4. anonymous
    • 5 years ago
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    ok what would be the answer

  5. anonymous
    • 5 years ago
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    how would i find the x

  6. anonymous
    • 5 years ago
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    well, you have the total area of the big rectangle, and both lengths in terms of x

  7. anonymous
    • 5 years ago
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    could you solve it for me so the width would be?

  8. anonymous
    • 5 years ago
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    you can solve it, it's easy from here.

  9. anonymous
    • 5 years ago
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    so what do i fill in for x

  10. anonymous
    • 5 years ago
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    x is the width of the path. you want to find out what that is. right now you have an equation that is (one side)*(other side)=total area. you have both the sides in terms of x, and the total area is given in the question. all you have to do from there put all the numbers on one side of the equation and have one x on the other side.

  11. anonymous
    • 5 years ago
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    do i add or multiply the sides

  12. anonymous
    • 5 years ago
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    multiply. it's the equation for the area of a rectangle, which is length times breadth. you only add the sides together to find perimeters.

  13. anonymous
    • 5 years ago
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    i cant get it

  14. anonymous
    • 5 years ago
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    what specifically are you getting stuck on?

  15. anonymous
    • 5 years ago
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    hello?

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