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anonymous
 5 years ago
curvilinear motion: parametric equations: y(t)=4.9t^2 +4.864t+1.2192 and x(t)=5.08t... i found the equations for velocity individually etc etc. Find the formula for the speed of the particle at any time, t?
anonymous
 5 years ago
curvilinear motion: parametric equations: y(t)=4.9t^2 +4.864t+1.2192 and x(t)=5.08t... i found the equations for velocity individually etc etc. Find the formula for the speed of the particle at any time, t?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need to derive the equations individually, then take \[(dy/dt)/(dx/dt)\] to find the velocity at any time, you should have t in the equation as f(t) = velocity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so \[(9.8t+4.864)/5.08\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but isint dy/dx just height in terms of distance? not speed in terms of time?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(−9.8t+4.864)/5.08 is correct.... NO dy/dx means the change in y(dependent variable) divided by the change in x (independent variable)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can apply this concept to the rate of people per room, rate of population per year, and many more.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i see! because i am simply dividing the rates of distance while keeping it in terms of time, i keep the integrity of the independent variable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem ... keep up the good work... math is all about the notation... if you understand that the logic will become easier.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the next question asks to find dy/dx ... O.o
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