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anonymous

  • 5 years ago

curvilinear motion: parametric equations: y(t)=-4.9t^2 +4.864t+1.2192 and x(t)=5.08t... i found the equations for velocity individually etc etc. Find the formula for the speed of the particle at any time, t?

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  1. anonymous
    • 5 years ago
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    you need to derive the equations individually, then take \[(dy/dt)/(dx/dt)\] to find the velocity at any time, you should have t in the equation as f(t) = velocity

  2. anonymous
    • 5 years ago
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    so \[(-9.8t+4.864)/5.08\]?

  3. anonymous
    • 5 years ago
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    but isint dy/dx just height in terms of distance? not speed in terms of time?

  4. anonymous
    • 5 years ago
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    (−9.8t+4.864)/5.08 is correct.... NO dy/dx means the change in y(dependent variable) divided by the change in x (independent variable)

  5. anonymous
    • 5 years ago
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    you can apply this concept to the rate of people per room, rate of population per year, and many more.

  6. anonymous
    • 5 years ago
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    oh i see! because i am simply dividing the rates of distance while keeping it in terms of time, i keep the integrity of the independent variable

  7. anonymous
    • 5 years ago
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    thank you so much

  8. anonymous
    • 5 years ago
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    no problem ... keep up the good work... math is all about the notation... if you understand that the logic will become easier.

  9. anonymous
    • 5 years ago
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    the next question asks to find dy/dx ... O.o

  10. anonymous
    • 5 years ago
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    :D

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