anonymous
  • anonymous
how do you solve x^2-2xy=6 by implicit differentiation?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[= 2x -2yy'\]\[y' = -2x/2y \] \[y' = -\]
anonymous
  • anonymous
y' = -x/y *
anonymous
  • anonymous
correct me if I'm wrong ^_^

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anonymous
  • anonymous
dy/dx(x^2-2xy=6) = 2x(dx)-(2y(dx)+2x(dy)=0 =2x(dx)-2y(dx)-2x(dy)=0 =(dx)(2x-2y)=2x(dy) =(2x-2y)=2x(dy/dx) (dy/dx)=(2x-2y)/(2x) (dy/dx)=(x-y)/(x)
anonymous
  • anonymous
lol, right! I forgot abt the 2xy, arman's answer is correct ^_^
anonymous
  • anonymous
the book says the answer is 1- y/x
anonymous
  • anonymous
yeah same thing
anonymous
  • anonymous
hmm, let me write it down on paper
anonymous
  • anonymous
(x-y)/(x) =(x/x)-(y/x) =1-(y/x)
anonymous
  • anonymous
exactly
anonymous
  • anonymous
:-)
anonymous
  • anonymous
did you understand it lefty? :)
anonymous
  • anonymous
lots of use of distribution, and dont forget your product rule! :O
anonymous
  • anonymous
you got that right, how can I forget such thing >_<
anonymous
  • anonymous
yup, your above walkthrough i will figure out. thank you guys
anonymous
  • anonymous
thanks to arman :) good luck!
anonymous
  • anonymous
aha no worries, i messed up my quotient rule for the first 50+ pages of problem sets i did, i was devastated when i found out
anonymous
  • anonymous
yep yep good lucck
anonymous
  • anonymous
yeah it makes it even tougher my professor is a Romanian immigrant

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