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anonymous

  • 5 years ago

how do you solve x^2-2xy=6 by implicit differentiation?

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  1. anonymous
    • 5 years ago
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    \[= 2x -2yy'\]\[y' = -2x/2y \] \[y' = -\]

  2. anonymous
    • 5 years ago
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    y' = -x/y *

  3. anonymous
    • 5 years ago
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    correct me if I'm wrong ^_^

  4. anonymous
    • 5 years ago
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    dy/dx(x^2-2xy=6) = 2x(dx)-(2y(dx)+2x(dy)=0 =2x(dx)-2y(dx)-2x(dy)=0 =(dx)(2x-2y)=2x(dy) =(2x-2y)=2x(dy/dx) (dy/dx)=(2x-2y)/(2x) (dy/dx)=(x-y)/(x)

  5. anonymous
    • 5 years ago
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    lol, right! I forgot abt the 2xy, arman's answer is correct ^_^

  6. anonymous
    • 5 years ago
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    the book says the answer is 1- y/x

  7. anonymous
    • 5 years ago
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    yeah same thing

  8. anonymous
    • 5 years ago
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    hmm, let me write it down on paper

  9. anonymous
    • 5 years ago
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    (x-y)/(x) =(x/x)-(y/x) =1-(y/x)

  10. anonymous
    • 5 years ago
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    exactly

  11. anonymous
    • 5 years ago
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    :-)

  12. anonymous
    • 5 years ago
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    did you understand it lefty? :)

  13. anonymous
    • 5 years ago
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    lots of use of distribution, and dont forget your product rule! :O

  14. anonymous
    • 5 years ago
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    you got that right, how can I forget such thing >_<

  15. anonymous
    • 5 years ago
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    yup, your above walkthrough i will figure out. thank you guys

  16. anonymous
    • 5 years ago
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    thanks to arman :) good luck!

  17. anonymous
    • 5 years ago
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    aha no worries, i messed up my quotient rule for the first 50+ pages of problem sets i did, i was devastated when i found out

  18. anonymous
    • 5 years ago
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    yep yep good lucck

  19. anonymous
    • 5 years ago
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    yeah it makes it even tougher my professor is a Romanian immigrant

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spraguer (Moderator)
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