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anonymous

  • 5 years ago

sinxcosx(dy/dx)+y=sinx how to find y?

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  1. anonymous
    • 5 years ago
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    you mean y' right?

  2. anonymous
    • 5 years ago
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    y' = cosx ^_^

  3. anonymous
    • 5 years ago
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    wait a min, it's: y' + y = sinx

  4. anonymous
    • 5 years ago
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    right?

  5. anonymous
    • 5 years ago
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    if so, then y= sinx - y'

  6. anonymous
    • 5 years ago
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    y'=(sinx-y)/(sinxcosx) ? i dont fully understand the question DX

  7. anonymous
    • 5 years ago
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    lol no, the question is : y' + y = sinx

  8. anonymous
    • 5 years ago
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    whats the sinxcosx?

  9. anonymous
    • 5 years ago
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    wait....it's the derivative of sinxcosx + y = sinx

  10. anonymous
    • 5 years ago
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    so y = sinx + sin^x + cos^2x = sinx + 1 = sinx

  11. anonymous
    • 5 years ago
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    sin^2x*

  12. anonymous
    • 5 years ago
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    there's something wrong ._.

  13. anonymous
    • 5 years ago
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    whats wrong?

  14. anonymous
    • 5 years ago
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    mowazzem can you please restate the question

  15. anonymous
    • 5 years ago
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    in a more understandable way

  16. anonymous
    • 5 years ago
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    sinxcosxy'+y=sinx

  17. anonymous
    • 5 years ago
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    find y' or y?

  18. anonymous
    • 5 years ago
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    its a derivative, i need to solve this

  19. anonymous
    • 5 years ago
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    that's mean y

  20. anonymous
    • 5 years ago
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    you want to derive y = sinx - sinxcosx?

  21. anonymous
    • 5 years ago
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    linear homogeneous

  22. anonymous
    • 5 years ago
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    again, mowa is this the question you want to derive: y = sinx - sinxcosx?

  23. anonymous
    • 5 years ago
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    no this is not a question. its a DERIVATIVE FORM sinxcosx(y')+y=sinx

  24. anonymous
    • 5 years ago
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    and you want to find y?

  25. anonymous
    • 5 years ago
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    yeah

  26. anonymous
    • 5 years ago
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    then y = sinx - sinxcosxy'

  27. anonymous
    • 5 years ago
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    as far as I have understood from the problem

  28. anonymous
    • 5 years ago
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    wait, do you want to integrate?!

  29. anonymous
    • 5 years ago
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    right hand side has also a derivative of y'. so your suggestion might be worng

  30. anonymous
    • 5 years ago
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    lol! so you DO want to integrate ^_^

  31. anonymous
    • 5 years ago
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    what class is this? calculus or diff equas?

  32. anonymous
    • 5 years ago
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    I think it's calculus since she wants to get y

  33. anonymous
    • 5 years ago
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    diff equas

  34. anonymous
    • 5 years ago
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    only way to get rid of y' is to integrate

  35. anonymous
    • 5 years ago
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    oh, no wonder, diff euas (at that level) are just beyond me

  36. anonymous
    • 5 years ago
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    just a little*

  37. anonymous
    • 5 years ago
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    mowa, did you take integration by parts?

  38. anonymous
    • 5 years ago
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    sstaica what do you do?

  39. anonymous
    • 5 years ago
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    did you take integration?

  40. anonymous
    • 5 years ago
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    do you know bernoulli equation

  41. anonymous
    • 5 years ago
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    heard of it

  42. anonymous
    • 5 years ago
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    y'+p(x)y=r(x)

  43. anonymous
    • 5 years ago
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    general form of bernoullis equation

  44. anonymous
    • 5 years ago
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    its semelar form of previous equation

  45. anonymous
    • 5 years ago
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    hmm, the bernoulli that I know comes from physics P + 1/2pV^2 + pgh

  46. anonymous
    • 5 years ago
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    are undergraduate student

  47. anonymous
    • 5 years ago
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    you mean a college student?

  48. anonymous
    • 5 years ago
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    yeah

  49. anonymous
    • 5 years ago
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    yep I am, first year ^_^

  50. anonymous
    • 5 years ago
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    or graduate student

  51. anonymous
    • 5 years ago
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    why? :)

  52. anonymous
    • 5 years ago
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    ok, probably you don't know

  53. anonymous
    • 5 years ago
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    are you a graduate?

  54. anonymous
    • 5 years ago
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    its higher class math

  55. anonymous
    • 5 years ago
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    I am doing PhD

  56. anonymous
    • 5 years ago
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    I see, then you are right, I prolly don't know it :) still taking calculus II ^_^

  57. anonymous
    • 5 years ago
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    whoa! GOOD LUCK :)

  58. anonymous
    • 5 years ago
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    i know that why you usde very simple rule

  59. anonymous
    • 5 years ago
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    lol, still learning ^^" anyways, sorry for not being able to help , I wish I could help though, you can try google? or youtube ^_^

  60. anonymous
    • 5 years ago
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    and I wish you the best of luck :)

  61. anonymous
    • 5 years ago
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    its very simple but I forgot. I done it about 4 yrs ago.

  62. anonymous
    • 5 years ago
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    you can try google though , the only way I know right now is integration by parts

  63. anonymous
    • 5 years ago
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    anyaway thanks

  64. anonymous
    • 5 years ago
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    np ^_^

  65. anonymous
    • 5 years ago
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    haha yup diff equas are some crazy fun stuff XD

  66. anonymous
    • 5 years ago
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    mowazzem, can i ask you a question?

  67. anonymous
    • 5 years ago
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    sorry i am going out. What you wanna ask?

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