anonymous
  • anonymous
sinxcosx(dy/dx)+y=sinx how to find y?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
you mean y' right?
anonymous
  • anonymous
y' = cosx ^_^
anonymous
  • anonymous
wait a min, it's: y' + y = sinx

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anonymous
  • anonymous
right?
anonymous
  • anonymous
if so, then y= sinx - y'
anonymous
  • anonymous
y'=(sinx-y)/(sinxcosx) ? i dont fully understand the question DX
anonymous
  • anonymous
lol no, the question is : y' + y = sinx
anonymous
  • anonymous
whats the sinxcosx?
anonymous
  • anonymous
wait....it's the derivative of sinxcosx + y = sinx
anonymous
  • anonymous
so y = sinx + sin^x + cos^2x = sinx + 1 = sinx
anonymous
  • anonymous
sin^2x*
anonymous
  • anonymous
there's something wrong ._.
anonymous
  • anonymous
whats wrong?
anonymous
  • anonymous
mowazzem can you please restate the question
anonymous
  • anonymous
in a more understandable way
anonymous
  • anonymous
sinxcosxy'+y=sinx
anonymous
  • anonymous
find y' or y?
anonymous
  • anonymous
its a derivative, i need to solve this
anonymous
  • anonymous
that's mean y
anonymous
  • anonymous
you want to derive y = sinx - sinxcosx?
anonymous
  • anonymous
linear homogeneous
anonymous
  • anonymous
again, mowa is this the question you want to derive: y = sinx - sinxcosx?
anonymous
  • anonymous
no this is not a question. its a DERIVATIVE FORM sinxcosx(y')+y=sinx
anonymous
  • anonymous
and you want to find y?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
then y = sinx - sinxcosxy'
anonymous
  • anonymous
as far as I have understood from the problem
anonymous
  • anonymous
wait, do you want to integrate?!
anonymous
  • anonymous
right hand side has also a derivative of y'. so your suggestion might be worng
anonymous
  • anonymous
lol! so you DO want to integrate ^_^
anonymous
  • anonymous
what class is this? calculus or diff equas?
anonymous
  • anonymous
I think it's calculus since she wants to get y
anonymous
  • anonymous
diff equas
anonymous
  • anonymous
only way to get rid of y' is to integrate
anonymous
  • anonymous
oh, no wonder, diff euas (at that level) are just beyond me
anonymous
  • anonymous
just a little*
anonymous
  • anonymous
mowa, did you take integration by parts?
anonymous
  • anonymous
sstaica what do you do?
anonymous
  • anonymous
did you take integration?
anonymous
  • anonymous
do you know bernoulli equation
anonymous
  • anonymous
heard of it
anonymous
  • anonymous
y'+p(x)y=r(x)
anonymous
  • anonymous
general form of bernoullis equation
anonymous
  • anonymous
its semelar form of previous equation
anonymous
  • anonymous
hmm, the bernoulli that I know comes from physics P + 1/2pV^2 + pgh
anonymous
  • anonymous
are undergraduate student
anonymous
  • anonymous
you mean a college student?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
yep I am, first year ^_^
anonymous
  • anonymous
or graduate student
anonymous
  • anonymous
why? :)
anonymous
  • anonymous
ok, probably you don't know
anonymous
  • anonymous
are you a graduate?
anonymous
  • anonymous
its higher class math
anonymous
  • anonymous
I am doing PhD
anonymous
  • anonymous
I see, then you are right, I prolly don't know it :) still taking calculus II ^_^
anonymous
  • anonymous
whoa! GOOD LUCK :)
anonymous
  • anonymous
i know that why you usde very simple rule
anonymous
  • anonymous
lol, still learning ^^" anyways, sorry for not being able to help , I wish I could help though, you can try google? or youtube ^_^
anonymous
  • anonymous
and I wish you the best of luck :)
anonymous
  • anonymous
its very simple but I forgot. I done it about 4 yrs ago.
anonymous
  • anonymous
you can try google though , the only way I know right now is integration by parts
anonymous
  • anonymous
anyaway thanks
anonymous
  • anonymous
np ^_^
anonymous
  • anonymous
haha yup diff equas are some crazy fun stuff XD
anonymous
  • anonymous
mowazzem, can i ask you a question?
anonymous
  • anonymous
sorry i am going out. What you wanna ask?

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