anonymous 5 years ago THE SIDE OF A PARALLELOGRAM IS 1/4 THE LENGTH OF ITS BASE. THE PARALLELOGRAM'S PERIMETER IS 125. WHAT IS THE BASE AND THE SIDE OF THE PARALLELOGRAM?

Again, if you let the base of the parallelogram be b, and the side s, you're told,$s=\frac{1}{4}b$You're also told that the perimeter is 125; that is,$2s+2b=125$You can sub. the first equation for s into the second to find for b,$2(\frac{1}{4}b)+2b=125 \rightarrow \frac{1}{2}b+2b=\frac{5}{2}b=125$Multiply both sides by 2, then divide both sides by 5. You get,$b=50$Since $s=\frac{1}{4}b \rightarrow s=\frac{50}{4}=\frac{25}{2}=12.5$