DELMA IS MAKING A PICTURE FRAME. SHE WANTS TO GLUE GOLD BRAID AROUND THE EDGE OF THE FRAME. THE FRAME IS 9IN. x 14IN. WHAT IS THE LEAST AMOUNT OF BRAID DELMA WILL NEED? IF BRAID IS SOLD BY THE YARD AND FRACTIONS OF A YARD HOW MUCH SHOULD DELMA BUY?

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DELMA IS MAKING A PICTURE FRAME. SHE WANTS TO GLUE GOLD BRAID AROUND THE EDGE OF THE FRAME. THE FRAME IS 9IN. x 14IN. WHAT IS THE LEAST AMOUNT OF BRAID DELMA WILL NEED? IF BRAID IS SOLD BY THE YARD AND FRACTIONS OF A YARD HOW MUCH SHOULD DELMA BUY?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I guess the frame is rectangular
and since she's glueing them on the edge then I guess you should take the perimeter which is the sum of the sides: P = 2L + 2W = 2(14) + 2(9) = 46 in She'll need 46 inches. Correct me if I'm wrong ^_^
alina, this is correct also. You just need to finish it off. You know you need 46 inches of braiding. There are 36 inches in every yard, so you'll need \[\frac{46}{36}=\frac{36+10}{36}=\frac{36}{36}+\frac{10}{36}=1+\frac{5}{18}=1\frac{5}{18}yards\]

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(46 inches of braid)/(36 inches for every yard) - you need to figure out how many yards fit into 46 inches, which is what I calculated for you above. Does this help?

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