anonymous
  • anonymous
The speed of sound in the air is proportional to the square root of the absolute temperature. At 20 °C the speed of sound is 343 m/s. What is the speed of sound at –10 °C? (0 °C = 273 K).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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nowhereman
  • nowhereman
Just solve: \[ \frac{x}{\sqrt{273 - 10}} = \frac{343}{\sqrt{273+20}} \] because that is what proportional means.
anonymous
  • anonymous
how do you get kelvin from celcius?
nowhereman
  • nowhereman
It's just a simple translation [K] = [C] + 273.15, but you should see this from my previous answer.

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anonymous
  • anonymous
am i not supposed to use something like \[(spped of sound) \alpha temperature ^{2}\] ?
anonymous
  • anonymous
speed = k * temperature ^ 2
anonymous
  • anonymous
?
nowhereman
  • nowhereman
No, you said yourself, that the speed of sound v is proportional to the square root of the temperature T, so \[v \sim \sqrt{T} ⇔ ∃ k: v = k\cdot \sqrt{T}\]
anonymous
  • anonymous
oh, i get it
anonymous
  • anonymous
thanx
anonymous
  • anonymous
so, is the answer 325? because thats what i got
anonymous
  • anonymous
anwar, can you please fan lokisan, because he helped me alot and i can only fan him once
nowhereman
  • nowhereman
Yes, 325 is about right. A more exact value I got, using 1 deg C = 273.15 K, is 324.975677595.

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