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 3 years ago
An engine burns 1.4 kg of gasoline per hour and yields 3.5 kW of power.
Calculate the efficiency of the engine when the heating value of gasoline is
43 MJ/kg.
 3 years ago
An engine burns 1.4 kg of gasoline per hour and yields 3.5 kW of power. Calculate the efficiency of the engine when the heating value of gasoline is 43 MJ/kg.

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BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0i dont even know where to start

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0ANY help, even a formula or a rule or a hint, anything will help

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0i just know efficiency = input/output

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0oh, sorry, it is output/input

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0ok,.... i am calm

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0The heating value is the amount of heat energy produced by complete combustion in a given quantity. Take a basis of 1 hour. Then your engine burns 1.4kg of gasoline, which yields a maximal amount of thermal energy to use for work as\[43MJ/kg \times 1.4 kg=60.2MJ\]In one hour, your engine produces from this energy, \[\frac{3500J}{s}\times \frac{3600s}{h}=12.6MJ\]The efficiency is the amount of work per unit energy input, which is \[\eta = \frac{12.6MJ}{60.2MJ}=0.209\]to 3 significant figures.

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0This is the first time I've used 'heating value' for anything like this, so if the answer's wrong, I couldn't find an appropriate definition.

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0so, can i say that efficiancy is 20.9%?

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0ok, thank you, i already faned you long time ago, so cant fan again :(

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah I know  no worries :)

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0The answer makes sense  I've seen values between 10 and 50% for internal combustion engines.

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0then it is probably correct, i also know that cobustion engines are very unefficient

AnwarA
 3 years ago
Best ResponseYou've already chosen the best response.0would you be one if I say yes?

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0anwar, can you please fan lokisan, because he helped me alot and i can only fan him once

AnwarA
 3 years ago
Best ResponseYou've already chosen the best response.0lol you really care about others :P.. I already did anyways

AnwarA
 3 years ago
Best ResponseYou've already chosen the best response.0so you faned me just as an exchange for me to fan the guy huh? :(

BecomeMyFan=D
 3 years ago
Best ResponseYou've already chosen the best response.0nah, would have faned you anyway

sstarica
 3 years ago
Best ResponseYou've already chosen the best response.0lol andy, you and your fanning job~ ^_^
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