anonymous
  • anonymous
(2x+4y)/(x^2-y^2) times (x+y)/(x^2+4xy+4y^2) just checking is this the right answer? 2/(x62-y^2) ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
sorry I meant 2/(x^2-y^2)
anonymous
  • anonymous
no
anonymous
  • anonymous
ok could you explain what I got wrong?

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anonymous
  • anonymous
\[2/(x^2 +xy-2y^2)\]
anonymous
  • anonymous
I need to see your solution in order to find your mistake/ It's just regular stuff
anonymous
  • anonymous
Here's how I factored it out: \[2(x+2y)/(x+y)(x-y) \times (x+y)/(x+2y)(x+2y)\]
anonymous
  • anonymous
then, I removed (x+y) from denominator and numerator, and then (x+2y) to simplify
anonymous
  • anonymous
leaving me with 2/(x-y)(x+2y)
anonymous
  • anonymous
then I multiplied the fractions
anonymous
  • anonymous
ohhh wait now I see what I got wrong...I forgot about the 2 factor in 2y...but thanks anyway... :)
anonymous
  • anonymous
u got mistake at the very end? welcome
anonymous
  • anonymous
\[(x-y)(x+2y)=x^2+xy-2y^2\]
anonymous
  • anonymous
(x^2-y^2) is equal to (x+y)(x-y), not (x-y)(x+2y)
anonymous
  • anonymous
sorry, i had to sign up to reply so it took super long lol
anonymous
  • anonymous
its ok lol thanks for trying! haha

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