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anonymous

  • 5 years ago

(2x+4y)/(x^2-y^2) times (x+y)/(x^2+4xy+4y^2) just checking is this the right answer? 2/(x62-y^2) ?

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  1. anonymous
    • 5 years ago
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    sorry I meant 2/(x^2-y^2)

  2. anonymous
    • 5 years ago
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    no

  3. anonymous
    • 5 years ago
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    ok could you explain what I got wrong?

  4. anonymous
    • 5 years ago
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    \[2/(x^2 +xy-2y^2)\]

  5. anonymous
    • 5 years ago
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    I need to see your solution in order to find your mistake/ It's just regular stuff

  6. anonymous
    • 5 years ago
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    Here's how I factored it out: \[2(x+2y)/(x+y)(x-y) \times (x+y)/(x+2y)(x+2y)\]

  7. anonymous
    • 5 years ago
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    then, I removed (x+y) from denominator and numerator, and then (x+2y) to simplify

  8. anonymous
    • 5 years ago
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    leaving me with 2/(x-y)(x+2y)

  9. anonymous
    • 5 years ago
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    then I multiplied the fractions

  10. anonymous
    • 5 years ago
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    ohhh wait now I see what I got wrong...I forgot about the 2 factor in 2y...but thanks anyway... :)

  11. anonymous
    • 5 years ago
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    u got mistake at the very end? welcome

  12. anonymous
    • 5 years ago
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    \[(x-y)(x+2y)=x^2+xy-2y^2\]

  13. anonymous
    • 5 years ago
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    (x^2-y^2) is equal to (x+y)(x-y), not (x-y)(x+2y)

  14. anonymous
    • 5 years ago
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    sorry, i had to sign up to reply so it took super long lol

  15. anonymous
    • 5 years ago
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    its ok lol thanks for trying! haha

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spraguer (Moderator)
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