## anonymous 5 years ago (2x+4y)/(x^2-y^2) times (x+y)/(x^2+4xy+4y^2) just checking is this the right answer? 2/(x62-y^2) ?

1. anonymous

sorry I meant 2/(x^2-y^2)

2. anonymous

no

3. anonymous

ok could you explain what I got wrong?

4. anonymous

$2/(x^2 +xy-2y^2)$

5. anonymous

I need to see your solution in order to find your mistake/ It's just regular stuff

6. anonymous

Here's how I factored it out: $2(x+2y)/(x+y)(x-y) \times (x+y)/(x+2y)(x+2y)$

7. anonymous

then, I removed (x+y) from denominator and numerator, and then (x+2y) to simplify

8. anonymous

leaving me with 2/(x-y)(x+2y)

9. anonymous

then I multiplied the fractions

10. anonymous

ohhh wait now I see what I got wrong...I forgot about the 2 factor in 2y...but thanks anyway... :)

11. anonymous

u got mistake at the very end? welcome

12. anonymous

$(x-y)(x+2y)=x^2+xy-2y^2$

13. anonymous

(x^2-y^2) is equal to (x+y)(x-y), not (x-y)(x+2y)

14. anonymous