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anonymous
 5 years ago
__5x___=(x5)=1(underneath 1 is 1
x5 = x5
I hope this isn't confusing I was just trying to show how my problem looks on the page with the 5x being over the x5. It is a very simple problem but I am just asking about if my thought process is right by knowing that the two x5's cancel each other and so we are just left with the 1 on the top and the regular 1 on the bottom
anonymous
 5 years ago
__5x___=(x5)=1(underneath 1 is 1 x5 = x5 I hope this isn't confusing I was just trying to show how my problem looks on the page with the 5x being over the x5. It is a very simple problem but I am just asking about if my thought process is right by knowing that the two x5's cancel each other and so we are just left with the 1 on the top and the regular 1 on the bottom

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you're right :), but you can simplify 1/1 to 1

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0yes, but you must remember, that x can not be 5, because 0/0 is not defined

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, thank you so much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have another question about this kind of rational expression

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I had an x^23x with a 2x6 on the bottom of that. I understand that the x^23x breaks up into subsequent parentheses of (x+3x) (x3x) do I just leave the 2x6 alone as it is on the bottom?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0That sounds strange, if I understood you correctly you must calculate \[ \frac{x^2  3x}{2x 6} = \frac{x\cdot(x3)}{2\cdot(x3)} = \frac{x}{2}\]
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