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anonymous
 5 years ago
A television camera is positioned 10000 ft from the base of a rocket launching pad. The angle of elevation of the camera has to change at the correct rate in order to keep the rocket in sight. Also, the mechanism for focusing the camera has to take into account the increasing distance from the camera to the rising rocket. Let's assume the rocket rises vertically and its speed is 800 ft/s when it has risen 24000 ft. (Round the answers to three decimal places.)
(a) How fast is the distance from the television camera to the rocket changing at that moment?
anonymous
 5 years ago
A television camera is positioned 10000 ft from the base of a rocket launching pad. The angle of elevation of the camera has to change at the correct rate in order to keep the rocket in sight. Also, the mechanism for focusing the camera has to take into account the increasing distance from the camera to the rising rocket. Let's assume the rocket rises vertically and its speed is 800 ft/s when it has risen 24000 ft. (Round the answers to three decimal places.) (a) How fast is the distance from the television camera to the rocket changing at that moment?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its easy....first let the camera and rocket in line position..,,,when the rocket has risen find the distance between rocket and camera by using phytagoras theorema.. \[\sqrt{10000^2+ 24000^2}\] = 676000000 ft then v =x \t t can be found,,then the velocity of rocket from camera view can be found by the same equation..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dr/dt = dr/dy * dy/dt or implicitly derive the pythagorean theorum and fill in what you know :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Ill implicit it... x^2 + y^2 = r^2 10000^2 = r^2  y^2 dx/dt 2(10000) = dr/dt 2r  dy/dt 2y divide it all by "2" to simplify: (dx/dt) 10000 = (dr/dt)r  (dy/dt)y dx/dt = 0 ; dy/dt = 800 ; y=24000; and r= sqrt(10000^2  24000^2) 0 = (dr/dt)sqrt(10000^2  24000^2)  (800)(24000) solve for dr/dt...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dr/dt = 800(24000)  sqrt(10000^2  24000^2) happy number crunching :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(10000^2 + 24000) sneaky little bugger it is :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your smart; youll be able to read thru the typos lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Just for eruditional purposes..... dr/dt = 800(24000)  sqrt(10000^2 + 24000^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0...... murmur...... still got errors in it..... if you can work the algebra, be by guest :) 0 = (dr/dt)sqrt(10000^2 + 24000^2)  (800)(24000) (800)(24000) = (dr/dt)sqrt(10000^2 + 24000^2) (800)(24000)  = (dr/dt) sqrt(10000^2 + 24000^2) Maybe? with a little luck? better double check it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sure, thanks yahoo, thank you so much, answer is correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0LOL .... that makes us BOTH happy :)
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