A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Find the equation of the circle.
x^2+y^2+Dx+Ey+F=0
that passes through the points: (2,0)(1,3)(5,3)
anonymous
 5 years ago
Find the equation of the circle. x^2+y^2+Dx+Ey+F=0 that passes through the points: (2,0)(1,3)(5,3)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0simply input the points to the equation. when you put (2,0) you got equation1. : (2)^2 +2D +F = 0 => 2D+F=4 Then the (1,3) and (5,3) so that you get 2 more equations : equation 2: D3E+F=10 and equation 3: 5D3E+F =34 then if you do elimination on equation 2 and 3, so that you'll get 6D=24 . Therefore D= 4 then put the value of D on equation 1. you'll get F=4+8 = 4. then put the value of D and F to equation 2 or 3 and you'll get E=18. Therefore the equation of the circle is : x^2 + y^2  4x  18y +4 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think i got the value of E wrong. the value of E should be 6 . then the right equation is ^2 + y^2  4x  6y +4 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ups sorry ,typo. the equation is x^2 + y^2  4x + 6y +4 = 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0WOw this makes a lot more sense than my book! Thank you!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.