Find the equation of the circle. x^2+y^2+Dx+Ey+F=0 that passes through the points: (2,0)(-1,-3)(5,-3)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Find the equation of the circle. x^2+y^2+Dx+Ey+F=0 that passes through the points: (2,0)(-1,-3)(5,-3)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

simply input the points to the equation. when you put (2,0) you got equation1. : (2)^2 +2D +F = 0 => 2D+F=-4 Then the (-1,-3) and (5,-3) so that you get 2 more equations : equation 2: -D-3E+F=-10 and equation 3: 5D-3E+F =-34 then if you do elimination on equation 2 and 3, so that you'll get -6D=24 . Therefore D= -4 then put the value of D on equation 1. you'll get F=-4+8 = 4. then put the value of D and F to equation 2 or 3 and you'll get E=-18. Therefore the equation of the circle is : x^2 + y^2 - 4x - 18y +4 = 0
i think i got the value of E wrong. the value of E should be 6 . then the right equation is ^2 + y^2 - 4x - 6y +4 = 0
ups sorry ,typo. the equation is x^2 + y^2 - 4x + 6y +4 = 0.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

WOw this makes a lot more sense than my book! Thank you!
you're welcome :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question