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anonymous
 5 years ago
Find the critical numbers for 8x12x^(2/3)
anonymous
 5 years ago
Find the critical numbers for 8x12x^(2/3)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To find a critical number you must first find the derivative of the function which is in this case:\[f'(x) = 8  8(x)^(1/3)\] then you take the 2 conditions for the critical numbers : 1) f'(x) = 0 2) f'(x) is undefined, hence we have Vertical Asymptotes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0give it a try now ^_^

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.08  (8/cbrt(x)) 8cbrt(x)  8  = 0 : when x = 1 cbrt(x) x = 1 is a critical number.... But is it a max or min? or even an inflection? test with the second derivative...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0If I did it right, its a minimum....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to find the critical points we derive once and to find the inflection points we derive twice ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0she just wants to find the critical numbers lol :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the one you have found is a critical number :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0actually, there are some instances where an inflection point has a 0 slope, so it is premature to say that y' = 0 is NOT an inflection.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all she wanted was the critical numbers ^_^

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep; and I think its 1 right? if I did it right :)
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