anonymous
  • anonymous
Find the critical numbers for 8x-12x^(2/3)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
To find a critical number you must first find the derivative of the function which is in this case:\[f'(x) = 8 - 8(x)^(-1/3)\] then you take the 2 conditions for the critical numbers : 1) f'(x) = 0 2) f'(x) is undefined, hence we have Vertical Asymptotes
anonymous
  • anonymous
give it a try now ^_^
amistre64
  • amistre64
8 - (8/cbrt(x)) 8cbrt(x) - 8 ---------- = 0 : when x = 1 cbrt(x) x = 1 is a critical number.... But is it a max or min? or even an inflection? test with the second derivative...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
If I did it right, its a minimum....
anonymous
  • anonymous
to find the critical points we derive once and to find the inflection points we derive twice ^_^
anonymous
  • anonymous
she just wants to find the critical numbers lol :)
anonymous
  • anonymous
so the one you have found is a critical number :)
amistre64
  • amistre64
actually, there are some instances where an inflection point has a 0 slope, so it is premature to say that y' = 0 is NOT an inflection.
anonymous
  • anonymous
all she wanted was the critical numbers ^_^
amistre64
  • amistre64
yep; and I think its 1 right? if I did it right :)
anonymous
  • anonymous
yes ^_^
amistre64
  • amistre64
whew!! .... :)
anonymous
  • anonymous
:D

Looking for something else?

Not the answer you are looking for? Search for more explanations.